\(4\left(x^2+15x+50\right)\left(x^2+18x+72\right)-3x^2\)

\(=4\left(x+5\right)\left(x+10\right)\left(x+12\right)\left(x+6\right)-3x^2\)

\(=4\left(x^2+17x+60\right)\left(x^2+16x+60\right)-3x^2\)

\(=4\left(x+60\right)^2+132x\left(x+60\right)+1088x^2-3x^2\)

\(=4\left(x+60\right)^2+132x\left(x+60\right)+1085x^2\)

\(=4\left(x+60\right)^2+62x\left(x+60\right)+70x\left(x+60\right)+1085x^2\)

\(=2\left(x+60\right)\left[2\left(x+60\right)+31x\right]+35x\left[2\left(x+60\right)+31x\right]\)

\(=\left(33x+120\right)\left(2x+120+35x\right)\)

\(=3\left(11x+40\right)\left(37x+120\right)\)

\(4\left(x^2+15x+50\right)\left(x^2+18x+72\right)+x^2\)

\(=4\left(x^2+5x+10x+50\right)\left(x^2+12x+6x+72\right)+x^2\)

\(=4\left(x+5\right)\left(x+10\right)\left(x+6\right)\left(x+12\right)+x^2\)

\(=4\left(x+6\right)\left(x+10\right)\left(x+5\right)\left(x+12\right)+x^2\)

\(=4\left(x^2+16x+60\right)\left(x^2+17x+60\right)+x^2\)

Đặt \(x^2+16x+60=a\)thay vào ta được :

\(4a\left(a+x\right)+x^2\)

\(=4a^2+4ax+x^2\)

\(=\left(2a+x\right)^2\)

\(=\left(2x^2+32x+120+x\right)^2\)

Chết lỡ enter rồi viết gọn nốt đoạn cuối giúp mình nhé :">

4(2-x)²+xy-2y = 4(x-2)²+y(x-2)=(x-2)(4x-8+y)

\(4\left(2-x\right)^2+xy-2y=4\left(x-2\right)^2+y\left(x-2\right)\)

\(=\left(x-2\right)\left(4\left(x-2\right)+y\right)\)

\(=\left(x-2\right)\left(4x+y-8\right)\)

Ta có: \(4\left(x-2\right)^2+xy-2y\)

\(=4\left(x-2\right)^2+y\left(x-2\right)\)

\(=\left(x-2\right)\left(4x-8+y\right)\)