4(2-x)2+xy-2y = 4(x-2)2+y(x-2)=(x-2)(4x-8+y)
\(4\left(2-x\right)^2+xy-2y=4\left(x-2\right)^2+y\left(x-2\right)\)
\(=\left(x-2\right)\left(4\left(x-2\right)+y\right)\)
\(=\left(x-2\right)\left(4x+y-8\right)\)
Ta có: \(4\left(x-2\right)^2+xy-2y\)
\(=4\left(x-2\right)^2+y\left(x-2\right)\)
\(=\left(x-2\right)\left(4x-8+y\right)\)