Thực hiện phép tính:
a) \(\frac{\left(2^3.3^3\right)^2.5^5}{\left(2^2\right).\left(3^2.5^2\right)^2}\)
b) \(\frac{2^3.11-2^3.8}{6.\left(-1\right)^{2014}}\)
THỰC HIỆN PHÉP TÍNH:
\(\frac{\left(2^3.3^3\right)^2.5^5}{\left(2^2\right)^3.\left(3^2.5^2\right)^2}\)
Tính \(A=-\frac{19}{2^3.3^2.5}+\left(-3\frac{1}{2}\right)^2:1,2-\left(-1\frac{1}{3}\right)^3:\frac{5}{6}\)
thực hiện phép tính
\(a=\left[\left(3^2.5^2.4^3\right):\left(2^3.3^2\right)\right].2005^0\)
\(a=\left[\frac{\left(3^2.5^2.4^3\right)}{\left(2^3.3^2\right)}\right].2005^0\)
\(\Rightarrow a=\left[\frac{5^2.4^3}{2^3}\right].1\)
\(a=\frac{5^2.2^3}{1}\)
a = 52 . 23 = 25 . 8
a = 200
\(\frac{\left(2^3.5^4.11\right).\left(2.5^3.11^2\right)}{\left(2^2.5^311\right)^2}\)
\(\frac{2^4.5^7.11^3}{2^4.5^611^2}=5.11=55\)
Thực hiện phép tính:
\(B=-\frac{1}{-77^2}.7^4\left(-11\right)^2.77^5.\left(\frac{1}{7^2}\right)^2:\left(7^3.11^6\right)\)
Thực hiện các phép tính (tính nhanh nhất nếu có thể):
\(A,\)\(2^2.5-\left(1^{10}+8\right):3^2\)
\(B, 5^8:5^6+4.(3^2-1)\)
\(C,\)\(400-\left\{36-20:\left[3^3-\left(8-3\right)\right]\right\}\)
a: \(2^2\cdot5-\dfrac{\left(1^{10}+8\right)}{3^2}\)
\(=4\cdot5-\dfrac{1+8}{3}\)
=20-3
=17
b: \(5^8:5^6+4\left(3^2-1\right)\)
\(=5^2+4\left(9-1\right)\)
=25+4*8
=25+32
=57
c: \(400-\left\{36-20:\left[3^3-\left(8-3\right)\right]\right\}\)
\(=400-36+20:\left[27-5\right]\)
\(=364+\dfrac{20}{22}\)
\(=364+\dfrac{10}{11}=\dfrac{4014}{11}\)
A) 2².5 - (1¹⁰ + 8) : 3²
= 4.5 - (1 + 8) : 9
= 20 - 9 : 9
= 20 - 1
= 19
B) 5⁸ : 5⁶ + 4.(3² - 1)
= 5² + 4.(9 - 1)
= 25 + 4.8
= 25 + 32
= 57
C) 400 - {36 - 20 : [3³ - (8 - 3)]}
= 400 - [36 - 20 : (27 - 5)]
= 400 -(36 - 20 : 22)
= 400 - (36 - 10/11)
= 400 - 386/11
= 4014/11
Thực hiện phép tính:
\(\frac{1}{-77^2}.7^4\left(-11\right)^2.77^5.\left(\frac{1}{7^2}\right)^2:\left(7^3.11^6\right)\)
\(\frac{\left(2^3.5^4.11\right).\left(2.5^3.11^2\right)}{\left(2^2.5^311\right)^2}\)
làm ơn hãy trả lời đi mình sẽ cho 1000 điểm
Thực hiện phép tính
a) \(\left[6.\left(-\frac{1}{3}\right)^2-3.\left(-\frac{1}{3}\right)+1\right]:\left(-\frac{1}{3}-1\right)\)
b) \(\frac{\left(\frac{2}{3}\right)^3.\left(-\frac{3}{4}\right)^2.\left(-1\right)^{2003}}{\left(\frac{2}{5}\right)^2.\left(-\frac{5}{12}\right)^3}\)