Các câu hỏi tương tự
thực hiện phép tính
\(a=\left[\left(3^2.5^2.4^3\right):\left(2^3.3^2\right)\right].2005^0\)
\(\frac{\left(2^3.5^4.11\right).\left(2.5^3.11^2\right)}{\left(2^2.5^311\right)^2}\)
Thực hiện các phép tính (tính nhanh nhất nếu có thể):
\(A,\)\(2^2.5-\left(1^{10}+8\right):3^2\)
\(B, 5^8:5^6+4.(3^2-1)\)
\(C,\)\(400-\left\{36-20:\left[3^3-\left(8-3\right)\right]\right\}\)
\(\frac{\left(2^3.5^4.11\right).\left(2.5^3.11^2\right)}{\left(2^2.5^311\right)^2}\)
Bài 1: Thực hiện phép tính
a) \(2^3+3.\left(\frac{1}{2}\right)^0+\left[\left(-2\right)^2:\frac{1}{2}\right]\)
b) \(\frac{2^{15}.9^4}{6^6.8^3}\)
c) \(\left(1+\frac{2}{3}-\frac{1}{4}\right).\left(\frac{4}{5}-\frac{3}{4}\right)^2\)
d) \(\left(\frac{-10}{3}\right)^3.\left(\frac{-6}{5}\right)^4\)
thực hiện các phép tính sau:
\(a,\left(4\frac{5}{37}-3\frac{4}{5}+8\frac{15}{29}\right)-\left(3\frac{5}{37}-6\frac{14}{29}\right)\)
\(b,\left(2\frac{5}{6}+1\frac{4}{9}\right):\left(10\frac{1}{12}-9\frac{1}{2}\right)\)
\(c,-\frac{2}{3}\left(8\frac{1}{2}-7.75\right):\frac{1}{3}+0.125:2\frac{2}{3}\)
Thực hiện phép tính : (Tính nhanh nếu có thể)
(\(\left(5+\frac{1}{5}-\frac{2}{9}\right)-\left(2-\frac{1}{23}-2\frac{3}{5}+\frac{5}{6}\right)-\left(8-\frac{2}{3}-\frac{1}{18}\right)\)
Tínha,frac{2^{10}cdot55+2^{10}cdot26}{2^8cdot27}b,120:{300:[150-(2.53-23.25)]}c,left[left(frac{40}{130}-frac{12}{13}right)cdot40%+0,15right]:frac{-5}{52}d,frac{0,8:left(frac{4}{5}cdot1,25right)}{0,64-frac{1}{25}}+frac{left(1,08-frac{2}{25}right):frac{4}{7}}{left(6frac{5}{9}-3frac{1}{4}right)cdot2frac{2}{17}}+left(1,2+0,5right):frac{1}{5}
Đọc tiếp
Tính
a,\(\frac{2^{10}\cdot55+2^{10}\cdot26}{2^8\cdot27}\)
b,120:{300:[150-(2.53-23.25)]}
c,\(\left[\left(\frac{40}{130}-\frac{12}{13}\right)\cdot40\%+0,15\right]:\frac{-5}{52}\)
d,\(\frac{0,8:\left(\frac{4}{5}\cdot1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right)\cdot2\frac{2}{17}}+\left(1,2+0,5\right):\frac{1}{5}\)
Bài 7 : Thực hiện phép tính :
a ) 5 - \(\left(-\frac{5}{11}\right)^0+\left(\frac{1}{3}\right)^2:3\)
b ) \(2^3+3.\left(\frac{1}{2}\right)^0+\left[\left(-2\right)^3:\frac{1}{2}\right]\)