b: \(\dfrac{1121}{1119}+\dfrac{1720}{217}=\dfrac{2167937}{119\cdot217}\)

a: \(150+50:5+2\cdot9\)

=150+10+18

=178

123

123

Bằng 123

\(3\frac{1}{1117}.\frac{4}{1119}-1\frac{1116}{1117}.5\frac{1118}{1119}-\frac{5}{1119}\)

\(=\frac{3352}{1117}.\frac{4}{1119}-\frac{2233}{1117}.\frac{6713}{1119}-\frac{5}{1119}\)

\(=\frac{1}{1119}\left(\frac{3352}{1117}.4-\frac{2233}{1117}.6713-5\right)\)

\(=\frac{1}{1119}\left(\frac{13408}{1117}-\frac{14990129}{1117}-\frac{5585}{1117}\right)\)

\(=\frac{1}{1119}.\frac{-14982306}{1117}\)

\(=\frac{-14982306}{1249923}\)

Đặt \(x=\frac{1}{1117}\) ,\(y=\frac{1}{1119}\)

Khi đó biểu thức có dạng \((3+x).4y-\left(1+1-x\right).\left(5+1-y\right)-5.y\)

\(=12y+4xy-\left(2-x\right)\left(6-y\right)-5y\)

\(=12y+4xy-\left(12-6x-2y+xy\right)-5y\)

\(=9y+3xy-12+6x\)

\(=\frac{9}{1119}+\frac{3}{1117.1119}-12+\frac{6}{1117}\)

\(=\frac{9.1117+3-12.1117.1119+6.1119}{1117.1119}\)

Ưm đến đây tự tính nha =)

Ta có:

$3^{39}=3^{3\times33}=(3^{3})^{33}=27^{33}>27^{21}$

Mà $11^{21}<27^{21}=>3^{39}>11^{21}$

3³⁹   = (3¹³)³

11²¹ = (11⁷)³

3¹³  = (3²)⁶.3 = 9⁶.3  < 11⁶. 11 = 11⁷

⇒ 3¹³ < 11⁷ ⇒ (3¹³)³ < (11⁷)³

⇒ 3³⁹ < 11²¹ 

ban viet de ra di :(

1934 + 1928+1231+1121+2422=8636

Ta có : 1934 + 1928 + 1231 + 1121 + 2422 = 8636

# chúc bạn học tốt #

Ta có:

\(5^{75}=\left(5^5\right)^{15}=3125^{15}\)

\(7^{60}=\left(7^4\right)^{15}=2401^{15}\)

Mà: \(3125^{15}>2401^{15}\)

\(\Rightarrow5^{75}>7^{60}\)

_______________

Ta có:

\(3^{39}< 3^{42}\); \(3^{42}=\left(3^6\right)^7=729^7\)

\(11^{21}=\left(11^3\right)^7=1331^7\)

Mà: \(729^7< 1331^7\)

\(\Rightarrow3^{42}< 11^{21}\)

\(\Rightarrow3^{39}< 11^{21}\)

a) \(5^{75}=\left(5^5\right)^{15}=3125^{15}\)

\(7^{60}=\left(7^4\right)^{15}=2401^{15}\)

mà \(2401^{15}< 3125^{15}\)

\(\Rightarrow5^{75}>7^{60}\)

b) \(3^{39}=\left(3^{13}\right)^3=1594323^3;11^{21}=\left(11^7\right)^3=19487171^3\)

mà \(19487171^3>1594323^3\)

\(\Rightarrow3^{39}< 7^{21}\)

5⁷⁵ = (5⁵)¹⁵= 3125¹⁵

7⁶⁰= (7⁴)¹⁵ = 2401¹⁵

Vì: 3125¹⁵ > 2401¹⁵ (3125 > 2401) => 5⁷⁵ > 7⁶⁰