Ta có: \(2x\left(3x-1\right)-\left(2x+1\right)\left(x-3\right)\)

\(=6x^2-2x-\left(2x^2-6x+x-3\right)\)

\(=6x^2-2x-2x^2+5x+3\)

\(=4x^2+3x+3\)

Ta có: \(3\left(x^2-2x\right)-\left(4x+2\right)\left(x-1\right)\)

\(=3x^2-6x-\left(4x^2-4x+2x-2\right)\)

\(=3x^2-6x-4x^2+2x+2\)

\(=-x^2-4x+2\)

\(2x\left(3x-1\right)-\left(2x+1\right)\left(x-3\right)=6x^2-2x-2x^2+5x+3=4x^2+3x+3\)

\(3\left(x^2-2x\right)-\left(4x+2\right)\left(x-1\right)=3x^2-6x-4x^2+2x-2=-x^2-4x-2\)

cậu xem câu hỏi của Quỳnh Phạm nha

a) Ta có: \(\left(x+1\right)\left(x^2-x+1\right)-\left(x-1\right)\left(x^2+x+1\right)\)

\(=x^3+1-x^3+1\)

=2

b) Ta có: \(\left(2x+3\right)\left(2x-3\right)-\left(2x+1\right)^2\)

\(=4x^2-9-4x^2-4x-1\)

\(=-4x-10\)

1) `2x(3x-1)-(2x+1)(x-3)`

`=6x^2-2x-2x^2+6x-x+3`

`=4x^2+3x+3`

2) `3(x^2-3x)-(4x+2)(x-1)`

`=3x^2-9x-4x^2+4x-2x+2`

`=-x^2-7x+2`

3) `3x(x-5)-(x-2)^2-(2x+3)(2x-3)`

`=3x^2-15x-(x^2-4x+4)-(4x^2-9)`

`=3x^2-15x-x^2+4x-4-4x^2+9`

`=-2x^2-11x+5`

4) `(2x-3)^2+(2x-1)(x+4)`

`=4x^2-12x+9+2x^2+8x-x-4`

`=6x^2-5x+5`

\(a,=x^2-6x+9-x^2+6x=9\\ b,=4x^2+4x+1-4x^2+9-4x-8=2\\ c,=\left(2x^2-2x-x+1\right):\left(x-1\right)\\ =\left(x-1\right)\left(2x-1\right):\left(x-1\right)=2x-1\)

`a)(x-3)^2-x(x-6)`

`=x^2-6x+9-x^2+6x=9`

`b)(2x+1)^2-(3+2x)(2x-3)-4(x+2)`

`=4x^2+4x+1-(4x^2-9)-4x-8`

`=2`

`c)(2x^2-3x+1):(x-1)`

`=(2x^2-2x-x+1):(x-1)`

`=[2x(x-1)-(x-1)]:(x-1)`

`=2x-1`

a) \(\left(x-3\right)^2-x\left(x-6\right)=x^2-6x+9-x^2+6x=9\)

b) \(\left(2x+1\right)^2-\left(3+2x\right)\left(2x-3\right)-4\left(x+2\right)=4x^2+4x+1-4x^2+9-4x-8=2\)

c) \(\left(2x^2-3x+1\right):\left(x-1\right)=\left[2x\left(x-1\right)-\left(x-1\right)\right]:\left(x-1\right)=\left[\left(x-1\right)\left(2x-1\right)\right]:\left(x-1\right)=2x-1\)

ĐKXĐ: \(x\notin\left\{1;\dfrac{1}{2}\right\}\)

\(\left(\dfrac{1}{x-1}+2+\dfrac{2x^3+x^2-x}{1-x^3}\right):\dfrac{1-2x}{x^3+x-2}\)

\(=\left(\dfrac{1}{x-1}+2-\dfrac{2x^3+x^2-x}{\left(x-1\right)\left(x^2+x+1\right)}\right)\cdot\dfrac{x^3+x-2}{1-2x}\)

\(=\dfrac{x^2+x+1+2\left(x^3-1\right)-2x^3-x^2+x}{\left(x-1\right)\left(x^2+x+1\right)}\cdot\dfrac{x^3-x^2+x^2-x+2x-2}{-\left(2x-1\right)}\)

\(=\dfrac{2x+1+2x^3-2-2x^3}{\left(x-1\right)\left(x^2+x+1\right)}\cdot\dfrac{\left(x-1\right)\left(x^2+x+2\right)}{-\left(2x-1\right)}\)

\(=\dfrac{2x-1}{x^2+x+1}\cdot\dfrac{-\left(x^2+x+2\right)}{2x-1}=\dfrac{-x^2-x-2}{x^2+x+1}\)

1:

a: \(\left(2x-5\right)^2-4x\left(x+3\right)\)

\(=4x^2-20x+25-4x^2-12x\)

=-32x+25

b: \(\left(x-2\right)^3-6\left(x+4\right)\left(x-4\right)-\left(x-2\right)\left(x^2+2x+4\right)\)

\(=x^3-6x^2+12x-8-\left(x^3-8\right)-6\left(x^2-16\right)\)

\(=-6x^2+12x-6x^2+96=-12x^2+12x+96\)

c: \(\left(x-1\right)^2-2\left(x-1\right)\left(x+2\right)+\left(x+2\right)^2+5\left(2x-3\right)\)

\(=\left(x-1-x-2\right)^2+5\left(2x-3\right)\)

\(=\left(-3\right)^2+5\left(2x-3\right)\)

\(=9+10x-15=10x-6\)

2: 

a: \(\left(2-3x\right)^2-5x\left(x-4\right)+4\left(x-1\right)\)

\(=9x^2-12x+4-5x^2+20x+4x-4\)

\(=4x^2+12x\)

b: \(\left(3-x\right)\left(x^2+3x+9\right)+\left(x-3\right)^3\)

\(=27-x^3+x^3-9x^2+27x-27\)

\(=-9x^2+27x\)

c: \(\left(x-4\right)^2\left(x+4\right)-\left(x-4\right)\left(x+4\right)^2+3\left(x^2-16\right)\)

\(=\left(x-4\right)\left(x+4\right)\left(x-4-x-4\right)+3\left(x^2-16\right)\)

\(=\left(x^2-16\right)\left(-8\right)+3\left(x^2-16\right)\)

\(=-5\left(x^2-16\right)=-5x^2+80\)

\(\left(x-2\right)^3+\left(2x+1\right)^2+2\left(x+2\right)\left(1-x\right)-9x^3+2x\)

\(=x^3-6x^2+12x-8+8x^3+12x^2+6x+1+2\left(x+2\right)\left(1-x\right)-9x^3+2x\)

\(=9x^3+6x^2+18x-7+2\left(x-x^2+2-2x\right)-9x^3+2x\)

\(=6x^2+20x-7-2x^2-2x+4=4x^2+18x-3\)

Trả lời:

( x - 2 )³ + ( 2x + 1 )³ + 2 ( x + 2 )( 1 - x ) - 9x³ + 2x

= x³ - 6x² + 12x - 8 + 8x³ + 12x² + 6x + 1 + 2 ( x - x² + 2 - 2x ) - 9x³ + 2x 

= 9x³ + 6x² + 18x - 7 + 2x - 2x² + 4 - 4x - 9x³ + 2x 

= 4x² + 18x - 3 

\(D=\left(2x+1\right)^2-\left(2x-3\right)^2+6x\)

\(D=\left(4x^2+4x+1\right)-\left(4x^2-12x+9\right)+6x\)

\(D=\left(4x^2-4x^2\right)+\left(4x-12x+6x\right)+\left(1-9\right)\)

\(D=-2x-8\)

_______________________

\(E=\left(x-4\right)^2-x\left(x+2\right)-2x+3\)

\(E=\left(x^2-8x+16\right)-\left(x^2+2x\right)-2x+3\)

\(E=\left(x^2-x^2\right)-\left(8x+2x+2x\right)+\left(16+3\right)\)

\(E=-12x+19\)

\(D=\left(2x+1\right)^2-\left(2x-3\right)^2+6x\)

\(D=\left[\left(2x\right)^2+2.2x.1+1^2\right]-\left[\left(2x\right)^2-2.2x.3+3^2\right]+6x\)

\(D=4x^2+4x+1-\left(4x^2-12x+9\right)+6x\)

\(D=4x^2+4x+1-4x^2+12x-9+6x\)

\(D=22x-8\)

___________

\(E=\left(x-4\right)^2-x\left(x+2\right)-2x+3\)

\(E=\left(x^2-2.x.4+4^2\right)-\left(x^2+2x\right)-2x+3\)

\(E=x^2-8x+16-x^2-2x-2x+3\)

\(E=-12x+19\)

a) Rút gọn biểu thức D = (2x + 1)2 - (2x - 3)2 + 6x:

Bắt đầu bằng việc mở ngoặc:
D = (4x^2 + 4x + 1) - (4x^2 - 12x + 9) + 6x

Tiếp theo, kết hợp các thành phần tương tự:
D = 4x^2 + 4x + 1 - 4x^2 + 12x - 9 + 6x

Tiếp tục đơn giản hóa:
D = 4x^2 - 4x^2 + 4x + 12x + 6x + 1 - 9

Kết quả cuối cùng:
D = 22x - 8

b) Rút gọn biểu thức E = (x - 4)2 - x(x + 2) - 2x + 3:

Bắt đầu bằng việc mở ngoặc:
E = (x^2 - 8x + 16) - (x^2 + 2x) - 2x + 3

Tiếp theo, kết hợp các thành phần tương tự:
E = x^2 - 8x + 16 - x^2 - 2x - 2x + 3

Tiếp tục đơn giản hóa:
E = x^2 - x^2 - 8x - 2x - 2x + 16 + 3

Kết quả cuối cùng:
E = -12x + 19

a)

\(2x\left(9-x\right)+\left(2x+5\right)\left(x+1\right)\\ =18x-2x^2+2x^2+5x+2x+5\\ =25x+5\\ =5\left(5x+1\right)\)

b)

\(\left(x-3\right)^2+\left(x+3\right)^2+2\left(3-x\right)\left(3+x\right)\\ =\left(3-x\right)^2+2\left(3-x\right)\left(3+x\right)+\left(3+x\right)^2\\ =\left[\left(3-x\right)+\left(3+x\right)\right]^2\\ =6^2=36\)