1. He has never gone abroad before.

2. She has driven for 1 month

3. We have eaten since it started to rain

4. I haven't had my hair cut when I left her

5. She hasn't kissed me for 5 months.

6. We haven't met for a long time.

7. How long have you had it?

8. I haven't had a delicious meal before

9. The last time I saw him was 8 days ago.

10. It is my first time I have ever taken bath since Monday

1. He hasn’t gone abroad before.

2. She has driven for a month.

3. We have already eaten when it rained.

4. I haven’t cut my hair since I left her.

5. She hasn’t kissed me for 5 months.

6. We haven’t met for a long time.

7. How long have you had it?

8. I haven’t had such a delicious meal before.

9. The last time I saw him was 8 days ago.

10. It is Monday since I last took a bath.

úi ùi ms lm dc 2 ceo:>

1.

a,\(BaCl_2+H_2SO_4\rightarrow BaSO_4\downarrow+2HCl\)

b, \(3Cu+8HNO_3\rightarrow3Cu\left(NO_3\right)_2+2NO\uparrow+H_2O\)

c, \(2NaOH+Ca\left(HSO_3\right)_2\rightarrow CaSO_3\downarrow+Na_2SO_3+2H_2O\)

\(13\left(x+45\right)=13^{29}:13^{27}\)

\(\Leftrightarrow13\left(x+45\right)=13^{29-27}\)

\(\Leftrightarrow13\left(x+45\right)=13^2\)

\(\Leftrightarrow x+45=13\)

\(\Leftrightarrow x=-32\)

13.(x+45)=13²⁹:13²⁷

13.(x+45)= 13^(29-27)

13.(x+45)= 13²

   x+45    = 13²:13

    x+45   =    13

    x+45    = 13-45

    x          = -32(t/m)

     Vậy x= -32

_K nha~

-------------------------------Hok Tốt--------------------------------

13(x+45)=\(13^{29}\):\(13^{27}\)

13(x+45)=\(13^2\)

13(x+45)=169

      x+45=169:13

      x+45=13

          x  =13-45

          x  = -32

\(C_4H_{10}\rightarrow C_2H_4\rightarrow C_2H_5OH\)

PT: \(C_4H_{10}\underrightarrow{cracking}C_2H_4+C_2H_6\)

\(C_2H_4+H_2O\rightarrow C_2H_5OH\)

1. B

2. C

3. C

4. B

5. A

6. D

7. C

8. C

9. A

10. B

1. B 2. C 3. C 4. B 5. A 6. D 7. C 8. C 9. A 10. B

Bài 8:

\(n_{Al}=\dfrac{2,7}{27}=0,1\left(mol\right)\)

\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)

0,1--->0,15------>0,05---------->0,15

a. \(V_{H_2SO_4}=\dfrac{0,15}{1}=0,15\left(l\right)=150\left(ml\right)\)

b. \(V'=0,15.22,4=3,36\left(l\right)\)

c. \(CM_{Al_2\left(SO_4\right)_3}=\dfrac{0,05}{0,15}=\dfrac{1}{3}M\)

Bài 9:

\(n_{Fe}=\dfrac{2,8}{56}=0,2\left(mol\right)\)

\(Fe+2HCl\rightarrow FeCl_2+H_2\)

0,2-->0,4---->0,2------>0,2

a. \(V_{HCl}=\dfrac{0,4}{1}=0,4\left(l\right)=400\left(ml\right)\)

b.\(V_{H_2}=0,2.22,4=4,48\left(l\right)\)

c. \(CM_{FeCl_2}=\dfrac{0,2}{0,4}=0,5M\)

Bài 10:

\(n_{H_2}=\dfrac{2,24}{22,4}=0,1\left(mol\right)\)

\(Fe+2HCl\rightarrow FeCl_2+H_2\)

0,1<--0,2<----0,1<----0,1

a. \(m=m_{Fe}=0,1.56=5,6\left(g\right)\)

b. \(V_{HCl}=\dfrac{0,2}{0,1}=2\left(l\right)=200\left(ml\right)\)

c.\(CM_{FeCl_2}=\dfrac{0,1}{2}=0,05M\)

Ở hình 2, kho sao chép nội dung từ ô E4 sang ô E5 thì nội dung ở ô E5 là: =$C$4*$D$4 vì ta đã cố định địa chỉ trong công thức

A

A : mang tính giáo dục 

A