(x+1/5)²+17/25=26/25

(x+1/5)²           =26/25-17/25

(x+1/5)²           =9/25

⇒(x+1/5)²=(3/5)² hoặc (x+1/5)²=(-3/5)²

    x+1/5=3/5 hoặc x+1/5=-3/5

       x=2/5 hoặc x=-4/5

Chúc bạn học tốt!

Ta có: \(\left(x+\dfrac{1}{5}\right)^2+\dfrac{17}{25}=\dfrac{26}{25}\)

\(\Leftrightarrow\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=\dfrac{-3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=\dfrac{-4}{5}\end{matrix}\right.\)

Vậy: \(x\in\left\{\dfrac{2}{5};\dfrac{-4}{5}\right\}\)

(x+1/5)²+17/25=26/25

(x+1/5)²           =26/25-17/25

(x+1/5)²           =9/25

⇒(x+1/5)²=(3/5)² hoặc (x+1/5)²=(-3/5)²

    x+1/5=3/5 hoặc x+1/5=-3/5

       x=2/5 hoặc x=-4/5

\(E=\dfrac{98:\left(\dfrac{4}{5}\cdot\dfrac{5}{4}\right)}{\dfrac{16}{25}-\dfrac{1}{25}}+\dfrac{\left(\dfrac{27}{25}-\dfrac{2}{25}\right)\cdot\dfrac{7}{4}}{\left(\dfrac{59}{9}-\dfrac{13}{4}\right)\cdot\dfrac{36}{17}}\\ E=\dfrac{98}{\dfrac{3}{5}}+\dfrac{\dfrac{7}{4}}{\dfrac{119}{36}\cdot\dfrac{36}{17}}\\ E=\dfrac{490}{3}+\dfrac{\dfrac{7}{4}}{7}=\dfrac{490}{3}+\dfrac{1}{4}=\dfrac{1963}{12}\)

\(\Leftrightarrow\left(\dfrac{13}{4}-x\right)\cdot\dfrac{101}{25}-\dfrac{1213}{100}=2\cdot\left[\left(x-\dfrac{10}{7}\right)\cdot\dfrac{49}{50}+\dfrac{2}{5}\right]\)

\(\Leftrightarrow\left(\dfrac{13}{4}-x\right)\cdot\dfrac{101}{25}=\dfrac{49}{25}\left(x-\dfrac{10}{7}\right)+\dfrac{4}{5}+\dfrac{1213}{100}\)

\(\Leftrightarrow\dfrac{1313}{100}-\dfrac{101}{25}x=\dfrac{49}{25}x-\dfrac{490}{175}+\dfrac{1293}{100}\)

=>-6x=13/5

hay x=-13/30

\(\left|\dfrac{2}{3}-1\right|-\dfrac{5}{2}.\sqrt[]{\dfrac{4}{25}}=\left|-\dfrac{1}{3}\right|-\dfrac{5}{2}.\dfrac{2}{5}=\dfrac{1}{3}-1=-\dfrac{2}{3}\)

-2/3

a: =>\(-\dfrac{6+x}{2}-\dfrac{3}{2}=2\)

=>-x-6-3=4

=>-x-9=4

=>-x=5

hay x=-5

b: =>(x+1)²=16

=>x+1=4 hoặc x+1=-4

=>x=3 hoặc x=-5

c: \(\Leftrightarrow\left(\dfrac{x-2}{27}-1\right)+\left(\dfrac{x-3}{26}-1\right)+\left(\dfrac{x-4}{25}-1\right)+\left(\dfrac{x-5}{24}-1\right)+\left(\dfrac{x-44}{5}+3\right)=0\)

=>x-29=0

hay x=29

5/2 - 1/4 + 5/3

= 10/4 - 1/4 + 5/3

= 9/4 + 5/3

= 27/12 + 20/12

= 47/12

11/2 : 1/4 x 5/3

= 11/2 x 4/1 x 5/3

= 44/2 x 5/3

= 220/6

= 110/3

14/5 x 2/3 + 5

= 28/15 + 5

= 28/15 + 75/15

= 103/15

nhớ ghi cách giải nha mình tick luôn

*Dấu gạch chéo (/) tượng trưng cho gạch ngang của phân số

1) Ta có: \(\left(-\dfrac{2}{3}\right)^2\cdot\dfrac{-9}{8}-25\%\cdot\dfrac{-16}{5}\)

\(=\dfrac{4}{9}\cdot\dfrac{-9}{8}-\dfrac{1}{4}\cdot\dfrac{-16}{5}\)

\(=\dfrac{-1}{2}+\dfrac{4}{5}\)

\(=\dfrac{-5}{10}+\dfrac{8}{10}=\dfrac{3}{10}\)

2) Ta có: \(-1\dfrac{2}{5}\cdot75\%+\dfrac{-7}{5}\cdot25\%\)

\(=\dfrac{-7}{5}\cdot\dfrac{3}{4}+\dfrac{-7}{5}\cdot\dfrac{1}{4}\)

\(=\dfrac{-7}{5}\left(\dfrac{3}{4}+\dfrac{1}{4}\right)=-\dfrac{7}{5}\)

3) Ta có: \(-2\dfrac{3}{7}\cdot\left(-125\%\right)+\dfrac{-17}{7}\cdot25\%\)

\(=\dfrac{-17}{7}\cdot\dfrac{-5}{4}+\dfrac{-17}{7}\cdot\dfrac{1}{4}\)

\(=\dfrac{-17}{7}\cdot\left(\dfrac{-5}{4}+\dfrac{1}{4}\right)\)

\(=\dfrac{17}{7}\)

4) Ta có: \(\left(-2\right)^3\cdot\left(\dfrac{3}{4}\cdot0.25\right):\left(2\dfrac{1}{4}-1\dfrac{1}{6}\right)\)

\(=\left(-8\right)\cdot\left(\dfrac{3}{4}\cdot\dfrac{1}{4}\right):\left(\dfrac{9}{4}-\dfrac{7}{6}\right)\)

\(=\left(-8\right)\cdot\dfrac{3}{16}:\dfrac{54-28}{24}\)

\(=\dfrac{-3}{2}\cdot\dfrac{24}{26}\)

\(=\dfrac{-72}{52}=\dfrac{-18}{13}\)

a: =11/2*4*5/3

=22*5/3

=110/3

b: =30/12-3/12+20/12

=47/12

c: =28/15+5

=28/15+75/15

=103/15

a: \(A=\left(\dfrac{\sqrt{x}}{\sqrt{x}+5}-1\right):\dfrac{25-x-x+9+x-25}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+5\right)}\)

\(=\dfrac{-5}{\sqrt{x}+5}\cdot\dfrac{\left(\sqrt{x}-3\right)\left(\sqrt{x}+5\right)}{-x+9}\)

\(=\dfrac{5\left(\sqrt{x}-3\right)}{x-9}=\dfrac{5}{\sqrt{x}+3}\)

b: Để A<1 thì A-1<0
\(\Leftrightarrow5-\sqrt{x}-3< 0\)

=>2-căn x<0

=>căn x>2

=>x>4