Tìm x:
\(2^x+2^{x+4}=544\)
2+4+6+...+x=544. Tìm x
tìm X
2x+2x+4=544
\(2^x+2^{x+4}=544\Leftrightarrow2^x\left(1+2^4\right)=544\)
\(\Leftrightarrow2^x=\frac{544}{17}=32=2^5\Rightarrow x=5\)
~ Học tốt ~
tìm x biết 2+4+6+...+x=544
tổng trên có số số hạng là: \(\frac{\left(x-2\right)}{2}+1=\frac{x}{2}-1+1=\frac{x}{2}\)
tổng của dãy là: \(\frac{\left(x+2\right)x}{2}=544\Leftrightarrow\frac{x^2}{2}+x-544=0\Leftrightarrow x^2+2x-1088=0\Leftrightarrow x^2-32x+34x-1008=0\Leftrightarrow\left(x-32\right)\left(x+34\right)=0\)
=> x=32(t/m) hoặc x=-34(loại)
=> x=32
2^x+2^(x+4)=544
2 mũ x +2 mũ (x+4)=544
Ta có : 2x + 2x + 4 = 544
=> 2x(1 + 24) = 544
=> 2x.17 = 544
=> 2x = 32
=> 2x = 25
=> x = 5
Vậy x = 5
Tìm x biết:
a) \(2^x+2^{x+4}=544\)
b) \(\left(\dfrac{2}{5}-3x\right)^2-\dfrac{1}{5}=\dfrac{4}{25}\)
\(a,\Leftrightarrow2^x\left(1+2^4\right)=544\\ \Leftrightarrow2^x=\dfrac{544}{17}=32=2^5\\ \Leftrightarrow x=5\\ b,\Leftrightarrow\left(\dfrac{2}{5}-3x\right)^2=\dfrac{9}{25}\Leftrightarrow\left[{}\begin{matrix}\dfrac{2}{5}-3x=\dfrac{3}{5}\\3x-\dfrac{2}{5}=\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=-\dfrac{1}{5}\\3x=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{15}\\x=\dfrac{1}{3}\end{matrix}\right.\)
Tìm x
2^x+2^x+4=544
cảm ơn đã trả lời kb nhé
Sửa lại đề
\(2^x+2^x+4=516\)
\(\Rightarrow2^x+2^x=512\)
\(\Rightarrow2^x+2^x=2^8+2^8\)
\(\Rightarrow x=8\)
hnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn
\(2^x+2^{x+4}=544\)
\(2^x\left(1+2^4\right)=544\)
\(2^x.17=544\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
tìm x biết 2+4+6+...=544
\(2^x+2^{x+4}=544\)
\(\Leftrightarrow2^x\left(1+2^4\right)=544\\ \Leftrightarrow2^x\cdot17=544\\ \Leftrightarrow2^x=32=2^5\Leftrightarrow x=5\)
2^x + 2^x+4 =544
\(2^x+2^{x+4}=544\\\Rightarrow2^x\cdot1+2^x\cdot2^4=544\\\Rightarrow2^x\cdot(1+2^4)=544\\\Rightarrow2^x\cdot(1+16)=544\\\Rightarrow2^x\cdot17=544\\\Rightarrow2^x=544:17\\\Rightarrow2^x=32\\\Rightarrow2^x=2^5\\\Rightarrow x=5\)
\(2^x+2^{x+4}=544\)
=>\(2^x+2^x\cdot2^4=544\)
=>\(2^x\left(1+2^4\right)=544\)
=>\(2^x\cdot17=544\)
=>\(2^x=\dfrac{544}{17}=32\)
=>\(2^x=2^5\)
=>x=5