b, B = 1.2 + 2.3 + 3.4 + ... + 99.100

3B = 1.2.3 + 2.3.3 + 3.4.3 + ... + 99.100.3

3B = 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 99.100.(101 - 98)

3B = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + 99.100.101 - 98.99.100

3B = 99.100.101

B = 99.100.101 : 3

B = 333300

Phép tính đâu bạn nhỉ?

a)\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)

\(=\frac{5}{9}:\left[\left(\frac{1}{11}-\frac{5}{22}\right)+\left(\frac{1}{15}-\frac{2}{3}\right)\right]\)

\(=\frac{5}{9}:\left[-\frac{3}{22}+-\frac{3}{5}\right]\)

\(=\frac{5}{9}:\frac{-81}{110}\)

\(=\frac{-550}{729}\)

Dễ mà

Bn quy đồng mẫu chung là(3+x)×(3-x)

a: \(=-\left(10x^2+15x-8x-12\right)=-10x^2-7x+12\)

-10x^2-7x+12

= 12-7x-10x^2

\(3^2\cdot5+2^3\cdot10-3^4:3\\ =9\cdot5+8\cdot10-3^4\\ =45+80-27\\ =98\)

\(3^2.5+2^3.10-3^4:3\)

\(=9.5+8.10-3^3\)

\(=45+80-27\)

\(=125-27\)

\(=98\)

\(#WendyDang\)

Anh ơi, dòng 2 ( \(3^4:3\) thì ra \(3^3\) -> a mới đổi thành được \(27\) chứ ạ? )

=2⁷ - 7²⁰²² 

=2⁷ - 7²⁰²² 

a, (y-476)x2=2196x3
(y-476)x2=2196x2+2196
(y-476)x2-2196x2=2196
(y-476-2196)x2=2196
(y-(476+2196)x2=2196
(y-2672)x2=2196
(y-2672)x2=1098x2
(y-2672)x2-1098x2=0
(y-2672-1098)x2=0
(y-(2672+1098)x2=0
(y-3770)x2=0
y-3770=0
y=3770
ĐS: y=3770

\(60-\left[15.2+\left(4+1^{35}\right)^2\right]\)
\(\Rightarrow60-\left[30+\left(4+1\right)^2\right]\)
\(\Rightarrow60-\left[30+25\right]\)
\(\Rightarrow60-55\)
\(\Rightarrow5\)

60-[30+(4+1)²

60-[30+25]

60-55

5