2:

a: n=5^4

=>n=625

b: n^3=125

=>n^3=5^3

=>n=5

c: 11^n=1331

=>11^n=11^3

=>n=3

\(=\left(-2\right)^6.5^3\)

a)(-8).(-2)^3.125=(-2)^3.(-2)^3.5^3=1^3=1

lm hộ mik câu này luôn nha

27.(-2)³.(+343)

\(a,5\cdot p\cdot5\cdot p\cdot2q\cdot4q\)

\(=5^2\cdot p^2\cdot2\cdot q\cdot2^2\cdot q\)

\(=5^2\cdot2^3\cdot p^2\cdot q^2\)

\(b,a\cdot a+b\cdot b+c\cdot c\cdot c+d\cdot d\cdot d\cdot d\)

\(=a^2+b^2+c^3+d^4\)

#Urushi

\(x^8:x^7:x=x^1:x=1^1\)

x⁸:x⁷:x=x^8-7-1=x⁰=1

x⁸ : x⁷ 

a) \(64^2\cdot32^4=2^{16}\cdot2^{20}=2^{36}\)

b) \(11^{16}\cdot5^{24}=\left(11^4\right)^4\cdot\left(5^6\right)^4=\left(11^4\cdot5^6\right)^4\)

a)64².32⁴=(2⁶)².(2⁵)⁴=2¹².2²⁰=2³²

b)11¹⁶.5²⁴(ko phân tích đc nữa)

voa2c0a94e3ca

`@` `\text {Ans}`

`\downarrow`

`a)`

\(2^{13}\cdot4^5\cdot8^2\)

`=`\(2^{13}\cdot\left(2^2\right)^5\cdot\left(2^3\right)^2\)

`=`\(2^{13}\cdot2^{10}\cdot2^6\)

`=`\(2^{29}\)

`b)`

\(100^6. 1000^4. 1000000\)^\(33\)

`=`\(10^{12}\cdot10^{12}\cdot10^{198}=10^{222}\)

`c)`

\(24^5. 6^5. 8^8\)

`=`\(2^{15}\cdot3^5\cdot2^5\cdot3^5\cdot2^{24}\)

`=`\(2^{15+5+24}\cdot3^{5+5}\)

`=`\(2^{44}\cdot3^{10}\) 

a, \(2^{13}\cdot4^5\cdot8^2=2^{13}\cdot2^{10}\cdot2^6=2^{19}.\)

b, \(100^6\cdot1000^4\cdot1000000^{33}=10^{12}\cdot10^{12}\cdot10^{198}=10^{222}.\)

c, \(24^5\cdot6^5\cdot8^8=2^{15}\cdot3^5\cdot2^5\cdot3^5\cdot2^{24}=2^{44}\cdot3^{10}.\)

a)  3.3^4.3^5 = 3^10

b) 7^3 : 7^2 : 7 = 7^0

c) (x^4)^3 = x^12

a) \(3\cdot3^4\cdot3^5=3^{10}\)

b) \(7^3:7^2:7=7^{3-2-1}=7^0\)

c) \(\left(x^4\right)^3=x^{12}\)

243 : 3³ : 3 = 3⁵ : 3³ : 3¹ = 3^{5 - 3 - 1} = 3¹

a, 243 : 3³ : 3= 3⁵ : 3³ : 3 = 3^5-3-1 = 3

hoctot