a)160-(23.52-6.25)

160-(1196-150)

160-1046

-886

b)4.52-32:24

208-4/3

620/3

c)5871:(928-(247-82).5)

5871:(928-165.5)

5871:(928-825)

5871:103

57

A, 160-(2^3.5^2-6.25)

160-50

=110

=> 110= 2.5.7

B,4.5^2-32:2^4

=4.25-32:16

=100-2

=98

=>98=2.7^2

Cau c mk giong kq vs bn tren

-886 nha 

\(160-\left(23,52-6,25\right)=160-17,27.\)

                                             \(=142,83\)   

Ủng hộ nhé

Hình như đề sai bạn à?

=160-(1196-150)

=160-1046

=-886

-886

a: 785+135-85+65

=785-85+135+65

=700+200

=900

b: \(32\cdot39+52\cdot21-12\cdot39+21\cdot48\)

\(=39\cdot32-12\cdot39+52\cdot21+21\cdot48\)

\(=39\left(32-12\right)+21\left(52+48\right)\)

\(=39\cdot20+21\cdot100=2100+780=2880\)

c: \(5^4\cdot5^8:5^9\cdot6\cdot8\cdot7\)

\(=\dfrac{5^{12}}{5^9}\cdot48\cdot7\)

\(=125\cdot48\cdot7=42000\)

d: \(2021^0-\left\{15^2:\left[175+\left(2^3\cdot5^2-6\cdot25\right)\right]\right\}\)

\(=1-\dfrac{225}{175+8\cdot25-150}\)

\(=1-\dfrac{225}{25+220}\)

=1-1

=0

a) 785 + 135 - 85 + 65 = 900

b) 32.39 + 52.21 - 12.39 + 21.48 = 93.69

c) 5 mũ 4.5 mũ  8 ÷ 5 mũ 9.6 ÷ 8.7 = 0.134

d) 2021 mũ 0 - { 15 mũ 2 : [ 175 + ( 2 mũ 3.5 mũ  2 - 6.25 ) ] } = 2021 mũ 0 - { 152 : [ 175 + 17.27 ] } = 20210 - { 152 : 192.27 } = 20210 - 0.791 = 20209.209

=4*25-32:16

=100-2

=98

\(4\cdot5^2-32:2^4\)

\(=4\cdot25-32:16\)

\(=100-2\)

\(=98\)

a) (-24) + 18 + 24 + (-28)

= (-24 + 24) + (18 - 28)

= 0 - 28

= -28

b) (-32) . 234 + 234

= 234 . (-32 + 1)

= 234 . (-31)

= -7254

a, (-24) + 18 + 24 +(-28)

= (-24) + 24 - (28 - 18)

= 0 - 10

= - 10 

b, (-32) x 234 + 234

= - 234 x ( 32  - 1)

= -234 x 31

= - 7254 

a) (-24) + 18 + 24 + (-28)

= [(-24) + 24] + 18 + (-28)

= 0 + 18 + (-28)

= 18 + (-28)

= (-10)

b) (-32) x 234 + 234

= (-32) x 234 + 234 x 1

= 234 x (-32 + 1)

= 234 x (-31)

= (-7254)

a,

\(\left(\frac{1}{2}\right)^{2x+1}=\frac{1}{32}\)

\(\left(\frac{1}{2}\right)^{2x+1}=\left(\frac{1}{2}\right)^5\)

=>\(2x+1=5\)

2x=5-1

2x=4

x=4:2

x=2

b, mình không biết cách làm 

a)\(\left(\frac{1}{2}\right)^{2x+1}=\frac{1}{32}\)

\(\left(\frac{1}{2}\right)^{2x+1}=\left(\frac{1}{2}\right)^5\)

\(\Rightarrow2x+1=5\)

\(\Rightarrow x=2\)

b,<=> |5 - x| = 0

          |x - 3| = 0

  <=> 5 - x = 0

         x - 3 = 0

<=> x = 5 - 0

       x = 0 + 3

<=> x = 5

       x = 3

Vậy x =3;5

răng toán lớp 7 mà dễ hơn lớp 6 ri