a) 105,6 - x = 29,04

x = 105,6 - 29,04

x = 76,56

b) x : 7 = 4,5 × 3

x : 7 = 13,5

x = 13,5 × 7

x = 94,5

c) Sửa đề: x × 2,8 + x × 5,2 = 48

x × (2,8 + 5,2) = 48

x × 8 = 48

x = 48 : 8

x = 6

d) Sửa đề:

x × 12,25 + x × 2,75 = 1050

x × (12,25 + 2,75) = 1050

x × 15 = 1050

x = 1050 : 15

x = 70

a) \(105,6-x=29,04\)

\(x=105,6-29,04\)

\(x=76,2\)

b) \(x:7=4,5x3\)

\(x:7=13,5\)

\(x=13,5x7\)

\(x=94,5\)

c) Bạn xem lại đề

d) Bạn xem lại đề

131 . x - 942 = 2^7 . 2^3 

131 . x - 942 = 2^10

131 . x - 942 = 1024

131 . x = 1024 + 942 

131 . x = 1966

x = 1966 : 131 

x \(\approx15\)

b ) [ ( x + 32 ) - 17 ] . 2 = 42 

     [ ( x + 32 ) - 17 ] = 42 : 2

     ( x + 32 ) - 17  = 21

     x + 32 = 21 + 17

     x + 32 = 38

     x = 38 - 32

    x = 6

A. 131.x-942=2^7.2^3

    131.x-942=1024

    131.x       =1966

       x           =1966/131

B. [(x+32)-17].2=42

     (x+32-17) .2 =42

     (x+15).2       =42

      x+15           = 21

     x                 =6

Câu1 bạn ko nêu rõ đầu bài cho lắm

Câu2 

Số phần tử là :

(60-6):2+1=28

Tổng là : 

(60+6)×28:2=924

Câu2 bạn ko nêu kết quả

dễ quá nhỉ

\(a,y\times2,8+5,2\times y=48\\ y\times\left(2,8+5,2\right)=48\\ y\times8=48\\ y=\dfrac{48}{8}=6\\ ---\\ b,y\times12,25-y+y\times2,75=1050\\ y\times\left(12,25-1+2,75\right)=1050\\ y\times14=1050\\ y=\dfrac{1050}{14}=75\)

a: \(y\cdot2,8+y\cdot5,2=48\)

=>\(y\left(2,8+5,2\right)=48\)

=>\(8y=48\)

=>\(y=\dfrac{48}{8}=6\)

b: \(y\cdot12,25-y+y\cdot2,75=1050\)

=>\(y\left(12,25-1+2,75\right)=1050\)

=>\(y\cdot14=1050\)

=>\(y=\dfrac{1050}{14}=75\)

\(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+.......+\dfrac{1}{x\cdot\left(x+1\right)}=\dfrac{122}{123}\)

\(\Leftrightarrow1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+......+\dfrac{1}{x}-\dfrac{1}{x+1}=\dfrac{122}{123}\)

\(\Leftrightarrow1-\dfrac{1}{x+1}=\dfrac{122}{123}\)

\(\Leftrightarrow\dfrac{1}{x+1}=\dfrac{1}{123}\)

\(\Leftrightarrow x=122\)

\(36\div\left[7.\left(x-3\right)+4\right]=6\)

\(\Rightarrow7.\left(x-3\right)+4=36\div6\)

\(\Rightarrow7.\left(x-3\right)+4=6\)

\(\Rightarrow7.\left(x-3\right)=6-4\)

\(\Rightarrow7.\left(x-3\right)=2\)

\(\Rightarrow x-3=2\div7\)

\(\Rightarrow x-3=\frac{2}{7}\)

\(\Rightarrow x=\frac{2}{7}+3\)

\(\Rightarrow x=\frac{23}{7}\)

\(36:\left[7.\left(x-3\right)+4\right]=6\)

\(7.\left(x-3\right)+4=36:6\)

\(7.\left(x-3\right)+4=6\)

\(7.\left(x-3\right)=6-4\)

\(7.\left(x-3\right)=2\)

\(x-3=2:7\)

\(x-3=\frac{2}{7}\)

\(x=\frac{2}{7}+3\)

\(x=\frac{23}{7}\)

c) x . (2,8 + 5,2) = 48 x . 8 = 48 x      = 48 : 8 x      = 6 d) x . (12,25 - 1 _ 2,75) = 1050     x . 14 = 1050     x        = 1050 : 14 = 75

c) \(x\times2,8+x\times5,2=48\)

\(x\times\left(2,8+5,2\right)=48\)

\(x\times8=48\)

\(x=6\)

d) \(x\times12,25-x+x\times2,75=1050\)

\(x\times\left(12,25-1+2,75\right)=1050\\ x\times14=1050\\ x=75\)