6. thực hiện phép tính
a. 128- [116-\(\left(132-128\right)^2\)]
b. 371+(-590)+(-271)+730
c. 279 - ( 145 +279)
d. 2341 - 243+(-2240)
e. -26 + 8 . ( 11+7)
g. 47 . ( 23+50) - 23. (47 +50)
1. thực hiện phép tính:
a. 483+(-56)+263+(-64)
b. 371+(-531)+(-271)+731
c. 3251-243-3250
d.279-(145+279)
1. Thực hiện phép tính :
a. 483 + (-56) + 263 + (-64)
= 427 + 263 + (-64)
= 690 + (-64)
= 262
b. 371 + (-531) + (-271) + 731
= (-160) + (-271) + 731
= (-431) + 731
= 300
c. 3251 - 243 - 3250
= 3008 - 3250
= -242
d. 279 - ( 145 + 276 )
= 279 - 421
= -142
tinh nhanh
a. 47.[23+50]-23.[47+50]
b,29.[85-47]+85.[47-29]
c,37.90-37.[-10]
d,15.12-3.5.10
e,29.[19-13]-19.[29-13]
f,33.[17-5]-17.[33-5]
g,54-6.[17+9]
h,1000+[-570]+2341+[-430]
nhiều quá mk phụ bạn chút thôi
a)47*(23+50)-23*(47+50)=47*23+47*50-23*47+23*50=(47*23-23*47)+(47*50+23*50)=(47+23)*50=70*50=3500
b)29*(85-47)+85*(47-29)=29*85-29*47+85*47-85*29=(29*85-85*29)+(85*47-29*47)=(85-29)*47=56*47=2632
c)37*90-37*(-10)=37*[90-(-10)]=37*100=3700
a. 47.[23+50]-23.[47+50]
=47.73-23.97
=3431-2231
=1200
b,29.[85-47]+85.[47-29]
=29.38+85.18
=1102+1520
=-428
c,37.90-37.[-10]
=37.(90-(-10))
=37.100
=3700
d,15.12-3.5.10
=15.12-15.10
=15.(12-10)
=15.2
=30
e,29.[19-13]-19.[29-13]
=29.6-19.16
=174-304
=-130
f,33.[17-5]-17.[33-5]
=33.12-17.32
=396-544
=-148
g,54-6.[17+9]
=54-6.26
=54-156
=-102
h,1000+[-570]+2341+[-430]
=430+2341+(-430)
=(-430+430)+2341
=0+2341
=2341
Thực hiện phép tính: (Tính nhanh nếu có thế)
1) 347.222-222.(216+184):8
2) 132-[116-(132-128)22]
3) 16:{400:[200-(37+46.3)]}
4) {184:[96-124:31]-2}.3651
5) ) 46 – [ (16 + 71 . 4 ) : 15 ]} – 2
6) 33.18 + 72 .42 – 41 .18
7)( 56 . 46 – 25 . 23 ) : 23
8) ( 28 . 54 + 56 . 36 ) : 21 : 2
9) ( 76 . 34 – 19 . 64 ) : ( 38 . 9 )
10) ( 2+ 4 + 6 + ….. + 100 ) . ( 36 . 333 – 108 . 111)
11) ( 5 . 411- 3 .165 ): 410
12) 7256.4375−725/3650+4375.7255
Giải;
1) \(347.222-222.\left(216+184\right):8\)
\(=347.222-222.400:8\)
\(=347.222-222.50\)
\(=222.\left(347-50\right)\)
\(=222.297\)
\(=65934\)
2) \(132-\left[116-\left(132-128\right).22\right]\)
\(=132-\left[116-4.22\right]\)
\(=132-\left[116-88\right]\)
\(=132-28\)
\(=104\)
3) \(16:\left\{400:\left[200-\left(37+46.3\right)\right]\right\}\)
\(=16:\left\{400:\left[200-\left(37+138\right)\right]\right\}\)
\(=16:\left\{400:\left[200-175\right]\right\}\)
\(=16:\left\{400:25\right\}\)
\(=16:16\)
\(=1\)
4) \(\left\{184:\left[96-124:31\right]-2\right\}.3651\)
\(=\left\{184:\left[96-4\right]-2\right\}.3651\)
\(=\left\{184:92-2\right\}.3651\)
\(=\left\{2-2\right\}.3651\)
\(=0.3651\)
\(=0\)
5) \(46-\left[\left(16+71.4\right):15\right]-2\)
\(=46-\left[\left(16+284\right):15\right]-2\)
\(=46-\left[300:15\right]-2\)
\(=46-20-2\)
\(=24\)
6) \(3^3.18+72.4^2-41.18\)
\(=18.\left(27-41\right)+72.16\)
\(=18.-14+1152\)
\(=-252+1152\)
\(=900\)
Giải: (tiếp)
7) \(\left(56.46-25.23\right):23\)
\(=\left(2576-575\right):23\)
\(=2001:23\)
\(=87\)
8) \(\left(28.54+56.36\right):21:2\)
\(=\left(1512+2016\right):21:2\)
\(=3528:21:2\)
\(=84\)
9) \(\left(76.34-19.64\right):\left(38.9\right)\)
\(=\left(2584-1216\right):342\)
\(=1368:342\)
\(=4\)
10) \(\left(2+4+6+...+100\right).\left(36.333-108.111\right)\)
\(=\left(2+4+6+...+100\right).\left(11988-11988\right)\)
\(=\left(2+4+6+...+100\right).0\)
\(=0\)
11) \(\left(5.4^{11}-3.16^5\right):4^{10}\)
\(=5.4^{11}:4^{10}-3.16^5:4^{10}\)
\(=5.4-3.1\)
\(=20-3\)
\(=17\)
12) \(7256.4375-725:3650+4375.7255\)
\(=4375.\left(7256+7255\right)-\dfrac{29}{146}\)
\(=4375.14511-\dfrac{29}{146}\)
\(=63485624,8\)
Câu 12 ko chắc!
Thực hiện các phép tính sau:
a) \(6 - 9\)
b) \(23 - \left( { - 12} \right)\)
c) \(\left( { - 35} \right) - \left( { - 60} \right)\)
d) \(\left( { - 47} \right) - 53\)
e) \(\left( { - 43} \right) - \left( { - 43} \right)\).
a) Số trừ là \(9\) có số đối là \(\left( { - 9} \right)\) nên ta có:
\(6 - 9 = 6 + \left( { - 9} \right) = - \left( {9 - 6} \right) = - 3\)
b) Số trừ là \(\left( { - 12} \right)\) có số đối là \(12\) nên ta có:
\(23 - \left( { - 12} \right) = 23 + 12 = 35\)
c) Số trừ là \(\left( { - 60} \right)\) có số đối là \(60\) nên ta có:
\(\begin{array}{l}\left( { - 35} \right) - \left( { - 60} \right) = \left( { - 35} \right) + 60\\ = 60 - 35 = 25\end{array}\)
d) Số trừ là \(53\) có số đối là \(\left( { - 53} \right)\) nên ta có:
\(\begin{array}{l}\left( { - 47} \right) - 53 = \left( { - 47} \right) + \left( { - 53} \right)\\ = - \left( {47 + 53} \right) = - 100\end{array}\)
e) Số trừ là \(\left( { - 43} \right)\) có số đối là 43 nên ta có:
\(\left( { - 43} \right) - \left( { - 43} \right) = \left( { - 43} \right) + 43 = 0\).
.Thực hiện phép tính
a) 47 – [(45.24 – 5 2 .12):14]
b) 50 – [(20 – 2 3 ) : 2 + 34]
c) 102 – [60 : (56 : 54 – 3.5)]
d) 50 – [(50 – 2 3 .5):2 + 3]
e) 10 – [(82 – 48).5 + (23 .10 + 8)] : 28
f) 8697 – [37 : 35 + 2(13 – 3)]
g) 2011 + 5[300 – (17 – 7)2 ]
h) 695 – [200 + (11 – 1)2 ]
k) 2345 – 1000 : [19 – 2(21 – 18)2 ]
l) 128 – [68 + 8(37 – 35)2 ] : 4
m) 568 – {5[143 – (4 – 1)2 ] + 10} : 10
n) 107 – {38 + [7.32 – 24 : 6+(9 – 7)3 ]}:15
o) 307 – [(180 – 160) : 22 + 9] : 2
p) 205 – [1200 – (42 – 2.3)3 ] : 40
q) 177 :[2.(42 – 9) + 32 (15 – 10)]
r) [(25 – 2 2 .3) + (32 .4 + 16)]: 5
i) 129 – 5[29 – (6 – 1)2 ]
j) 2010 – 2000 : [486 – 2(72 – 6)]
s) 125(28 + 72) – 25(32 .4 + 64)
t) 500 – {5[409 – (23 .3 – 21)2 ] + 103 } : 15
Sao bạn bỏ một khoảng trống giữa các số 5 2 với 2 3v?
Thực hiện phép tính:
a) 25 –[ 50 – ( 2 3 . 17 – 2 3 . 14 )]
b) |-128| : [ 45 2 – ( 2010 – 2008 0 . 1 2010 )]
a) 25 –[ 50 – ( 2 3 . 17 – 2 3 . 14 )]
= 25 – ( 50 – 23 . 3 ) = 25 – ( 50 – 24 )
= 25 – 26 = -1
b) |-128| : [ 45 2 – ( 2010 – 2008 0 . 1 2010 )]
= 128 : [ 2025 – ( 2010 – 1 . 1 )] = 128 : ( 2025 – 2009 ) = 128 : 16 = 8
Bài 5: Thực hiện phép tính:
a) 47 – [(45.24 – 52.12):14] | a) 3.52 + 15.22 – 26:2 |
b) 50 – [(20 – 23) : 2 + 34] | b) (- 25) . (- 4 ) + (- 70) . 3 |
c) 102 – [60 : (56 : 54 – 3.5)] | c) 62 : (- 9) - 50.2 – 33.(- 3) |
d) 50 – [(50 – 23.5):2 + 3] | d) 32.(- 50) - 23.10 – 81: (- 3) |
e) 10 – [(82 – 48).5 + (23.10 + 8)] : 28 | e) 513 : 510 – 25.22 |
f) 8697 – [37 : 35 + 2(13 – 3)] | f) 20 : 22 + 59 : 58 |
g) 2011 + 5[300 – (17 – 7)2] | g) 100 : 52 + 7.32 |
h) 695 – [200 + (11 – 1)2] | h) 84 : 4 + 39 : 37 + 50 |
i) 129 – 5[29 – (6 – 1)2] | i) 29 – [16 + 3.(51 – 49)] |
j) 2010 – 2000 : [486 – 2(72 – 6)] | j) 53.2 – 100 : 4 + 23.5 |
f: =20:4+5
=5+5
=10
e: =125-100=25
Thực hiện phép tính: (Tính nhanh nếu có thế)
1) 347.2\(^2\)-2\(^2\).(216+184):8
2) 132-[116-(132-128)\(^2\)]
3) 16:{400:[200-(37+46.3)]}
4) {184:[96-124:31]-2}.3651
5) ) 46 – [ (16 + 71 . 4 ) : 15 ]} – 2
6) 33.18 + 72 .42 – 41 .18
7)( 56 . 46 – 25 . 23 ) : 23
8) ( 28 . 54 + 56 . 36 ) : 21 : 2
9) ( 76 . 34 – 19 . 64 ) : ( 38 . 9 )
10) ( 2+ 4 + 6 + ….. + 100 ) . ( 36 . 333 – 108 . 111)
11) ( 5 . 411- 3 .165 ): 410
12) \(\dfrac{7256.4375-725}{3650+4375.7255}\)
thực hiện phép tính
A=47*63+47*17+80*53
B=(5*8+2*3-23*2)*(6^2016+7^2017+8^2018)