a) \(\dfrac{2^{14}.3^{12}}{6^{11}}\)

\(=\dfrac{2^2.2^{12}.3^{12}}{6^{11}}\)

\(=\dfrac{4.6^{12}}{6^{11}}\)

\(=4.6\)

\(=24\)

a) \(\dfrac{2^{14}.3^{12}}{6^{11}}=\dfrac{2^{14}.3^{12}}{2^{11}.3^{11}}=2^3.3\)

b) \(\dfrac{6^{18}}{9^9.8^5}=\dfrac{\left(2.3\right)^{18}}{\left(3^2\right)^8.\left(2^3\right)^5}\dfrac{2^{18}.3^{18}}{3^{18}.2^{15}}=2^3\)

a: \(\dfrac{2^{14}\cdot3^{12}}{6^{11}}=\dfrac{2^{14}\cdot3^{12}}{2^{11}\cdot3^{11}}=2^3\cdot3=24\)

b: \(\dfrac{6^{18}}{9^9\cdot8^5}=\dfrac{2^{18}\cdot3^{18}}{3^{18}\cdot2^{15}}=2^3\)

\(\frac{6^3+3.6^2+3^3}{-13}=\frac{2^3.3^3+3^3.2^2+3^3.1}{-13}=\frac{3^3\left(8+4+1\right)}{-13}=\frac{27.13}{-13}=\frac{-27}{ }\)

\(2^{27}=\left(2^3\right)^9=8^9\)

\(3^{18}=\left(3^2\right)^9=9^9\)

b) Vì 9 > 8 => 8⁹ < 9⁹

Vậy \(2^{27}

\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.3^6}{3^5.2^5.2^6}=\frac{2^7.3^6}{3^5.2^{11}}=\frac{3}{2^4}=\frac{3}{16}\)

Ta có : a) \(2^{24}=2^{6.4}=2^{4^6}=16^6\)

( số còn lại sai đề bạn ơi )

b) tương tự \(2^{27}=2^{3^9}=8^9\)

\(3^{18}=3^{2^9}=9^9\)

bài 2: a) \(x^{14}=x^7.x^7\)

b) chịu

c) \(x^{12}:x^{-2}\)

nhớ tick nhé!

1.
a) \(3^4\times3^5\times3^6=3^{4+5+6}=3^{15}\)

b) \(5^2\times5^4\times5^5\times25=5^2\times5^4\times5^5\times5^2=5^{2+4+5+2}=5^{13}\)

c) \(10^8\div10^3=10^{8-3}=10^5\)

d) \(a^7\div a^2=a^{7-2}=a^5\)

2.

\(987=900+80+7\\ =9\times100+8\times10+7\\ =9\times10^2+8\times10^1+7\times10^0\)

\(2021=2000+20+1\\ =2\times1000+2\times10+1\times1\\ =2\times10^3+2\times10^1+1\times10^0\)

\(abcde=a\times10000+b\times1000+c\times100+d\times10+e\times1\\ =a\times10^4+b\times10^3+c\times10^2+d\times10^1+e\times10^0\)

còn bài 2

Câu 3 :

A = 7776 . 8 - 2.243. 64

A = 62208 - 31104

A = 31104

Câu 1 :

a) \(12^5=3^5.4^5\)

b) \(20^6=4^6.5^6\)

c) \(54^3=6^3.9^3\)

Câu 2 :

a) \(3.5^{55}=3.\left(5^5\right)^{11}\)

b) \(4.3^{816}=4.\left(3^{17}\right)^{48}\)

c) \(9.8.7^{6412}=9.8.\left(7^{28}\right)^{229}\)

\(3^2\cdot3^4=3^{2+4}=3^6\)