Tính nhanh
a, \(-57\left(75-36\right)-75\left(36-57\right)\)
b, \(19-42\left(-19\right)+38.5\)
- Pờ li hép mi :<
\(A=5,3:\left(5\frac{5}{28}-2\frac{13}{36}+1\frac{16}{63}\right)\)
\(B=\left(\frac{19}{10}\times\frac{19}{10}+\frac{39}{2}:\frac{13}{3}\right)\times\left(\frac{62}{75}-\frac{12}{75}\right)\)
Tính nhanh các tổng sau :
a) \(\left(2736-75\right)-1736\)
b) \(\left(-2002\right)-\left(57-2002\right)\)
a) (2736 – 75) – 2736
= 2736 – 75 – 2736
= (2736 – 2736) – 75
= 0 – 75
= – 75
b) (- 2002) – (57 – 2002)
= (– 2002) – 57 + 2002
= (– 2002 + 2002) – 57
= 0 – 57
= – 57
a) (2736 – 75) - 2736
= 2736 - 75 – 2736 (bỏ dấu ngoặc có dấu "+" đằng trước)
= 2736 – 2736 - 75
= 0 - 75
= -75
2) – (57 - 2002)
= -2002 - 57 + 2002 (bỏ dấu ngoặc có dấu "-" đằng trước)
= -2002 + 2002 - 57
= 0 - 57
= -57
a)(2736-75) - 1736= 2736-75-1736=(2736-1736) -75 = 1000-75= 925
b) (-2002)-(57-2002)= -2002-57 + 2002= (-2002 + 2002) -57= 0-57=-57
tính giá trị biểu thức
a, A=\(\frac{-1}{2}-\left[\frac{-3}{5}\right]+\left[\frac{-1}{9}\right]+\frac{1}{27}+\frac{7}{18}+\frac{4}{35}-\left[-\frac{2}{7}\right]\)
b, B=\(\frac{1}{3}-\frac{3}{4}-\left[\frac{-3}{5}-\frac{1}{57}+\frac{1}{36}+\frac{-1}{15}\right]-\frac{2}{9}\)
c, C=\(\left[-\frac{7}{15}\right]\times\frac{5}{8}\times\left[\frac{30}{-7}\right]\times\left[-16\right]\times\left[\frac{-1}{1000}\right]\)
d, D=\(\frac{1}{2}\times\frac{-11}{19}-50\%\times\left[-\frac{1}{19}\right]+\frac{10}{19}\times\frac{1111}{2222}\)
tính giá trị biểu thức chứ còn cái gì nữa
a, \(A=\frac{22}{27}\)
b,\(B=\frac{1}{57}\)
C,\(C=\frac{1}{50}\)
d, \(D=0\)
BT2: Tính nhanh
7)\(\dfrac{-19}{34}\left(\dfrac{17}{19}+\dfrac{49}{18}\right)+\dfrac{49}{18}\left(\dfrac{19}{34}-\dfrac{18}{7}\right)\)
8)\(\dfrac{29}{32}\left(\dfrac{41}{36}-\dfrac{32}{58}\right)-\dfrac{41}{36}\left(\dfrac{29}{32}+\dfrac{18}{41}\right)\)
7)\(\dfrac{-19}{34}\left(\dfrac{17}{19}+\dfrac{49}{18}\right)+\dfrac{49}{18}\left(\dfrac{19}{34}-\dfrac{18}{7}\right)\)
=\(\dfrac{-19}{34}.\dfrac{17}{19}+\dfrac{49}{18}.\dfrac{-19}{34}+\dfrac{49}{18}.\dfrac{19}{34}-\dfrac{18}{7}.\dfrac{49}{18}\)
=\(\dfrac{1}{2}+\left(\dfrac{49}{18}.\dfrac{-19}{34}+\dfrac{49}{18}.\dfrac{19}{34}\right)-7\)
=\(\dfrac{1}{2}+\left[\dfrac{49}{18}\left(\dfrac{-19}{34}+\dfrac{19}{34}\right)\right]-7\)
=\(\dfrac{1}{2}+0-7=\dfrac{-13}{2}\)
8)\(\dfrac{29}{32}\left(\dfrac{41}{36}-\dfrac{32}{58}\right)-\dfrac{41}{36}\left(\dfrac{29}{32}+\dfrac{18}{41}\right)\)
=\(\dfrac{29}{32}.\dfrac{41}{36}-\dfrac{29}{32}.\dfrac{32}{58}-\dfrac{41}{36}.\dfrac{29}{32}+\dfrac{18}{41}.\dfrac{41}{36}\)
=\(\left(\dfrac{29}{32}.\dfrac{41}{36}-\dfrac{41}{36}\dfrac{29}{32}\right)-\dfrac{29}{32}.\dfrac{32}{58}+\dfrac{18}{41}.\dfrac{41}{36}\)
=\(0-\dfrac{1}{2}+\dfrac{1}{2}=0\)
Tính :
a) \(0+\left(-36\right)\)
b) \(\left|-29\right|+\left(-11\right)\)
c) \(75+\left(-325\right)\)
Tính giá trị của biểu thức sau một cách hợp lý
a) \(125.\left(-61\right).\left(-2\right)^3.\left(-1\right)^{2n}\left(n\inℕ^∗\right)\) c) \(-48.72+36.\left(-304\right)\)
b) \(136.\left(-47\right)+36.\left(-304\right)\)
d)\(-29\left(19-13\right)+19\left(29-13\right)\)
Các bạn jup mik nhanh nha, mik đang gấp. Thanks các bn nhiều, nhớ giải chi tiết ra nha
b) 136.(−47)+36.(−304)
= -6392 + -10944
= -17336
c) −48.72+36.(−304)
= -3456 + -10944
= -14400
d)−29.(19−13)+19.(29−13)
= -29 . 6 + 19 . 16
= -174 + 304
=130
# hok tốt #
Bỏ dấu ngoặc rồi tính:
a) \(\left( {4 + 32 + 6} \right) + \left( {10 - 36 - 6} \right)\)
b) \(\left( {77 + 22 - 65} \right) - \left( {67 + 12 - 75} \right)\)
c) \( - \left( { - 21 + 43 + 7} \right) - \left( {11 - 53 - 17} \right)\)
a)
Cách 1.
\(\begin{array}{l}\left( {4 + 32 + 6} \right) + \left( {10 - 36 - 6} \right)\\ = 4 + 32 + 6 + 10 - 36 - 6\\ = 52 + \left( { - 36} \right) + \left( { - 6} \right)\\ = 52 + \left( { - 42} \right) = 52 - 42 = 10\end{array}\)
Cách 2.
\(\begin{array}{l}\left( {4 + 32 + 6} \right) + \left( {10 - 36 - 6} \right)\\ = 4 + 32 + 6 + 10 - 36 - 6\\ = 36 + 6 + 10 + \left( { - 36} \right) + \left( { - 6} \right)\\ = 36 + \left( { - 36} \right) + 6 + \left( { - 6} \right) + 10\\ = 0 + 0 + 10 = 10\end{array}\)
b) \(\left( {77 + 22 - 65} \right) - \left( {67 + 12 - 75} \right)\)
\(\begin{array}{l} = 77 + 22 - 65 - 67 - 12 + 75\\ = 77 - 67 + 22 - 12 + 75 - 65\\ = 10 + 10 + 10 = 30\end{array}\)
c) \( - \left( { - 21 + 43 + 7} \right) - \left( {11 - 53 - 17} \right)\)
\(\begin{array}{l} = 21 - 43 - 7 - 11 + 53 + 17\\ = 21 - 11 + 53 - 43 + 17 - 7\\ = 10 + 10 + 10 = 30\end{array}\)
\(\left(57-725\right)-\left(605-53\right)\)
\(-452-\left(-67+75-452\right)\)
\(\left(55+45+15\right)-\left(15-55+45\right)\)
Mấy bài này bạn vận dụng qui tắc đổi dấu trong ngoặc và bấm máy tính bờ làm thôi
a,\(\left(57-725\right)-\left(605-53\right)\)
\(=57-725-605+53\)
\(=-1220\)
b,\(-452-\left(-67+75-452\right)\)
\(=-452+67-75+452\)
\(=-8\)
c,\(\left(55+45+15\right)-\left(15-55+45\right)\)
\(=55+45+15-15+55-45\)
\(=110\)
1 . Tinh : a , \(\left(1-\frac{1}{6}\right)\left(1-\frac{1}{10}\right)\left(1-\frac{1}{14}\right).....\left(1-\frac{1}{5050}\right)\)b,\(\frac{^{2^{19}}.\left(3^3\right)^3+3.5.\left(2^2\right)^9.\left(3^2\right)^4}{\left(2.3\right)^9.2^{10}+\left(3.2^2\right)^{10}}\)c,\(\frac{18.\frac{19}{2}.\frac{20}{3}.\frac{21}{4}.....\frac{36}{19}}{20.\frac{21}{2}.\frac{22}{3}.....\frac{36}{17}}\)giup mjk nha mjk tjk cho