`MSC:12`

`2/3=(2xx4)/(3xx4)=8/12` và `5/12`

`2/3=`\(\dfrac{2\times4}{3\times4}\)`=8/12` và `5/12`

Vì mẫu số chung là \(12\) nên phân số \(\dfrac{5}{12}\) không phải quy đồng .

Ta thấy \(12\div3=4\) vậy cả tử số và mẫu số của phân số \(\dfrac{2}{3}\) nhân với \(4\)

Ta có :

  \(\dfrac{2}{3}=\dfrac{2\times4}{3\times4}=\dfrac{8}{12}\)

Vậy hai phân số đó là : \(\dfrac{8}{12}\) và \(\dfrac{5}{12}\)

a: 11/8=99/72

-5/9=-40/72

-7/12=-42/72

a) \(\dfrac{3}{5}=\dfrac{21}{35};\dfrac{4}{7}=\dfrac{20}{35}\)

b) \(\dfrac{5}{6}=\dfrac{45}{54};\dfrac{7}{9}=\dfrac{42}{54}\)

a) \(\dfrac{2}{3}=\dfrac{2.8}{3.8}=\dfrac{16}{24}\)

\(\dfrac{5}{8}=\dfrac{5.3}{8.3}=\dfrac{15}{24}\)

b) \(\dfrac{1}{4}=\dfrac{1.3}{4.3}=\dfrac{3}{12}\)

\(\dfrac{7}{12}=\dfrac{7.1}{12.1}=\dfrac{7}{12}\)

c) \(\dfrac{5}{6}=\dfrac{5.4}{6.4}=\dfrac{20}{24}\)

\(\dfrac{3}{8}=\dfrac{3.3}{8.3}=\dfrac{9}{24}\)

a) 58=5.38.3=152458=5.38.3=1524

b) 712=7.112.1=712712=7.112.1=712

c) 38=3.38.3=924

a) 58=5.38.3=152458=5.38.3=1524

b) 712=7.112.1=712712=7.112.1=712

c) 38=3.38.3=924

a) \(\dfrac{3}{4}=\dfrac{3\cdot5}{4\cdot5}=\dfrac{15}{20}\\ \dfrac{2}{5}=\dfrac{2\cdot4}{5\cdot4}=\dfrac{8}{20}\)

b) \(\dfrac{5}{12}=\dfrac{5\cdot3}{12\cdot3}=\dfrac{15}{36}\\ \dfrac{11}{36}=\dfrac{11}{36}\)

c) \(\dfrac{2}{3}=\dfrac{2\cdot4\cdot5}{3\cdot4\cdot5}=\dfrac{40}{60}\\ \dfrac{3}{4}=\dfrac{3\cdot3\cdot5}{4\cdot3\cdot5}=\dfrac{45}{60}\\ \dfrac{4}{5}=\dfrac{4\cdot3\cdot4}{5\cdot3\cdot4}=\dfrac{48}{60}\)

a) \(\dfrac{3}{4}\) và \(\dfrac{2}{5}\)

Mẫu số chung: 20

\(\dfrac{3}{4}=\dfrac{3.5}{4.5}=\dfrac{15}{20}\)

\(\dfrac{2}{5}=\dfrac{2.4}{5.4}=\dfrac{8}{20}\)

b) \(\dfrac{5}{12}\) và \(\dfrac{11}{36}\)

Mẫu số chung: 36

\(\dfrac{5}{12}=\dfrac{5.3}{12.3}=\dfrac{15}{36}\)

c) \(\dfrac{2}{3};\dfrac{3}{4}\) và \(\dfrac{4}{5}\)

Mẫu số chung: 60

\(\dfrac{2}{3}=\dfrac{2.20}{3.20}=\dfrac{40}{60}\\ \dfrac{3}{4}=\dfrac{3.15}{4.15}=\dfrac{45}{60}\\ \dfrac{4}{5}=\dfrac{4.12}{5.12}=\dfrac{48}{60}\)

a) MTC=20

 \(\dfrac{3}{4}=\dfrac{15}{20}\)

\(\dfrac{2}{5}=\dfrac{8}{20}\)

b) MTC=36 

\(\dfrac{5}{12}=\dfrac{15}{36}\)

\(\dfrac{11}{36}=\dfrac{11}{36}\)

c) MTC=60

\(\dfrac{2}{3}=\dfrac{40}{60}\)

\(\dfrac{3}{4}=\dfrac{45}{60}\)

\(\dfrac{4}{5}=\dfrac{48}{60}\)

Ta có: \(\dfrac{5}{7} = \dfrac{{5.4}}{{7.4}} = \dfrac{{20}}{{28}}\) và \(\dfrac{{ - 3}}{4} = \dfrac{{ - 3.7}}{{4.7}} = \dfrac{{ - 21}}{{28}}\)

Như vậy, \(\dfrac{{20}}{{28}} + \dfrac{{ - 21}}{{28}} = \dfrac{{20 + \left( { - 21} \right)}}{{28}} =  \dfrac{-1}{{28}}\)

a: -5/5=-1=-7/7

8/7=8/7

b: -3/15=-1/5=-6/30

5/6=25/30

c: -34/136=-1/4=-9/36

-12/108=-1/9=-4/36

26/-156=-1/6=-6/36

1) 

\(\dfrac{3}{4}=\dfrac{3\times3}{4\times3}=\dfrac{9}{12}\) 

\(\dfrac{2}{12}\) (giữ nguyên)

2)

\(\dfrac{1}{4}=\dfrac{1\times3}{4\times3}=\dfrac{3}{12}\)

\(\dfrac{2}{3}=\dfrac{2\times4}{3\times4}=\dfrac{8}{12}\)

a) \(\dfrac{3}{4}\) và \(\dfrac{2}{12}\)

\(\dfrac{3}{4}=\dfrac{3\times3}{4\times3}=\dfrac{9}{12}\) ; giữ nguyên \(\dfrac{2}{12}\)

Quy đồng mẫu số hai phân số \(\dfrac{3}{4}\) và \(\dfrac{2}{12}\) được hai phân số \(\dfrac{9}{12}\) và \(\dfrac{2}{12}\).

b) \(\dfrac{1}{4}\) và \(\dfrac{2}{3}\)

\(\dfrac{1}{4}=\dfrac{1\times3}{4\times3}=\dfrac{3}{12}\) ; \(\dfrac{2}{3}=\dfrac{2\times4}{3\times4}=\dfrac{8}{12}\)

Quy đồng mẫu số hai phân số \(\dfrac{1}{4}\) và \(\dfrac{2}{3}\) được hai phân số \(\dfrac{3}{12}\) và \(\dfrac{8}{12}\).

\(\dfrac{2\times7}{5\times7}=\dfrac{14}{35};\dfrac{5\times5}{7\times5}=\dfrac{25}{35}\)

2/5 và 5/7 

\(\dfrac{2}{5}=\dfrac{2\times7}{5\times7}=\dfrac{14}{35}\)

\(\dfrac{5}{7}=\dfrac{5\times5}{7\times5}=\dfrac{25}{35}\)

\(\dfrac{2}{5}=\dfrac{2x7}{5x7}=\dfrac{14}{35}\\ \dfrac{5}{7}=\dfrac{5x5}{7x5}=\dfrac{25}{35}\)

a: \(\dfrac{5}{7}=\dfrac{5\cdot11}{7\cdot11}=\dfrac{55}{77}\)

\(\dfrac{9}{11}=\dfrac{9\cdot7}{11\cdot7}=\dfrac{63}{77}\)

b: \(\dfrac{36}{42}=\dfrac{6}{7}=\dfrac{6\cdot9}{7\cdot9}=\dfrac{54}{63}\)

\(-\dfrac{12}{54}=\dfrac{-2}{9}=\dfrac{-2\cdot7}{9\cdot7}=-\dfrac{14}{63}\)

c: \(\dfrac{-11}{30}=\dfrac{-11\cdot4}{30\cdot4}=\dfrac{-44}{120}\)

\(\dfrac{-17}{-40}=\dfrac{17}{40}=\dfrac{17\cdot3}{40\cdot3}=\dfrac{51}{120}\)

d: \(\dfrac{36}{42}=\dfrac{6}{7}=\dfrac{6\cdot3}{7\cdot3}=\dfrac{18}{21}\)

\(\dfrac{-12}{36}=\dfrac{-1}{3}=\dfrac{-1\cdot7}{3\cdot7}=\dfrac{-7}{21}\)