chọn B

B đúng

mình cảm ơn

bn cứ đăng đi sẽ có người giúp bn thôi

ok

Tính

\(D=\frac{5}{1.6}+\frac{5}{6.11}+\frac{5}{11.16}+...+\frac{5}{86.91}\)

\(=1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+\frac{1}{11}-\frac{1}{16}+...+\frac{1}{86}-\frac{1}{91}\)

\(=1-\frac{1}{91}=\frac{91}{91}-\frac{1}{91}=\frac{90}{91}\)

Vậy \(D=\frac{90}{91}.\)

\(D=\frac{5}{1.6}+\frac{5}{6.11}+\frac{5}{11.16}+...+\frac{5}{86.91}\)

\(=1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+\frac{1}{11}-\frac{1}{16}+....+\frac{1}{86}-\frac{1}{91}\)

\(=1-\frac{1}{91}\)

\(=\frac{91}{91}-\frac{1}{91}\)

\(=\frac{90}{91}\)

Vậy \(D=\frac{90}{91}\)

Chúc bạn học tốt !

\(\frac{17}{33}.\frac{2}{5}+\frac{3}{5}.\frac{17}{33}-\frac{17}{33}\)

\(=\frac{17}{33}\times\frac{2}{5}+\frac{3}{5}\times\frac{17}{33}-\frac{17}{33}\times1\)

\(=\frac{17}{33}\times\left(\frac{2}{5}+\frac{3}{5}-1\right)\)

\(=\frac{17}{33}\times\left(1-1\right)\)

\(=\frac{17}{33}\times0=\frac{17}{33}\)

 Làm he LÀM đi bạ nó lại  cồn bỏ bỏ

Qua N, kẻ tia Nz//Mx

Nz//Mx

=>\(\widehat{zNM}+\widehat{M}=180^0\)(hai góc trong cùng phía)

=>\(\widehat{zNM}=60^0\)

\(\widehat{zNM}+\widehat{zNP}=\widehat{MNP}\)

=>\(\widehat{zNP}=80^0-60^0=20^0\)

\(\widehat{zNP}=\widehat{P}\)

mà hai góc này ở vị trí so le trong

nên Nz//Py

=>Mx//Py

1/4

\(\dfrac{1}{3}+\dfrac{2}{5}+\dfrac{2}{3}+\dfrac{2}{3}\)

\(=\left(\dfrac{1}{3}+\dfrac{2}{3}\right)+\left(\dfrac{2}{5}+\dfrac{2}{3}\right)\)

\(=\dfrac{3}{3}+\dfrac{16}{15}\)

\(=1+\dfrac{16}{15}\)

\(=\dfrac{15}{15}+\dfrac{16}{15}\)

\(=\dfrac{31}{15}\)

\(\dfrac{1}{3}+\dfrac{2}{5}+\dfrac{2}{3}+\dfrac{2}{3}=\left(\dfrac{1}{3}+\dfrac{2}{3}\right)+\dfrac{2}{5}+\dfrac{2}{3}=1+\dfrac{2}{5}+\dfrac{2}{3}=\dfrac{5}{3}+\dfrac{2}{5}=\dfrac{5\times5+2\times3}{15}=\dfrac{31}{15}\)