Ý c là thực hiện phép tính nha mọi người

a/ \(\left(2n^3-5n^2+1\right):\left(2n-1\right)=n^2-2n-1\)

b/ \(x\ne0;\pm2\)

\(\left(\frac{x^2}{x\left(x^2-4\right)}-\frac{6}{3\left(x-2\right)}+\frac{1}{x+2}\right):\left(\frac{x^2-4+10-x^2}{x+2}\right)\)

\(=\left(\frac{x}{x^2-4}-\frac{2\left(x+2\right)}{x^2-4}+\frac{x-2}{x^2-4}\right):\left(\frac{6}{x+2}\right)\)

\(=\left(\frac{x-2x-4+x-2}{\left(x-2\right)\left(x+2\right)}\right).\left(\frac{x+2}{6}\right)\)

\(=\frac{-6}{\left(x-2\right)\left(x+2\right)}.\frac{\left(x+2\right)}{6}=-\frac{1}{x-2}=\frac{1}{2-x}\)

c/

\(\left(3x-1\right)^2+2\left(3x-1\right)\left(3x+4\right)+\left(3x+4\right)^2\)

\(=\left(3x-1+3x+4\right)^2\)

\(=\left(6x+3\right)^2\)

\(\left(3x^2-51\right)^{2n}=\left(-24\right)^{2n}\)

\(3x^2-51=-24\)

\(3x^2=27\)

\(x^2=9\)

\(x^2=3^2=\left(-3\right)^2\)

TH1: x=3

TH2: x=-3

=.= hok tốt!!

a: \(\left(3x^2-51\right)^{2n}=\left(-24\right)^{2n}=24^{2n}\)

\(\Leftrightarrow3x^2-51=24\) hoặc 3x²-51=-24

=>3x²=75 hoặc 3x²=27

=>x²=25 hoặc x²=9

hay \(x\in\left\{5;-5;3;-3\right\}\)

b: =>x-3>=0 và x-8<=0

=>3<=x<=8

\(\left(3x^2-51\right)^{2n}=\left(-24\right)^{2n}\)

\(\Leftrightarrow3x^2-51=-24\)

\(\Leftrightarrow3x^2=27\)

\(\Leftrightarrow x^2=9\)

\(\Leftrightarrow x=\pm3\)

(3x² - 51)²ⁿ = (-24)²ⁿ

=> \(\orbr{\begin{cases}3x^2-51=-24\\3x^2-51=24\end{cases}=>\orbr{\begin{cases}3x^2=27\\3x^2=75\end{cases}}}\) 

=>\(\orbr{\begin{cases}x^2=9\\x^2=25\end{cases}=>}\orbr{\begin{cases}x=3\\x=5\end{cases}}\)

a: \(=2x^{2n+1-2n}-2\cdot x^{2n}\cdot3\cdot x^{2-2n}+3\cdot x^{2n-1+1-2n}-9\cdot x^{2n-1+2-2n}\)

\(=2x-6x^2+3-9x\)

\(=-6x^2-7x+3\)

b: \(=\left(5x\right)^3-\left(2y\right)^3=125x^3-8y^3\)

\(\frac{3x}{5x+5y}-\frac{x}{10x-10y}\)

= \(\frac{3x\left(x-y\right)}{5.2.\left(x+y\right)\left(x-y\right)}-\frac{x\left(x+y\right)}{10\left(x^2-y^2\right)}\)

= \(\frac{3x^2-3xy-x^2-xy}{10\left(x^2-y^2\right)}\)

= \(\frac{3x\left(x-y\right)}{10\left(x^2-y^2\right)}\)

= \(\frac{3x}{10\left(x+y\right)}\)

a) 1/3x + 2/5x - 2/5 = 0

=> x = 0,54

b) 12n - 4n^2 - 18 + 6n +0

<=> -4n^2 + 6n - 18 = 0

<=> (-4n)^2 + 6n + 12n - 18 +0

<=> - 2n (2n-3 ) + 6 ( 2n - 3 ) = 0

,<=> ( 6 - 2n ) ( 2n -3 )=0

<=> 6 - 2n = 0 => n +3 / 2n-3 =0 => n = 3/2

a. (x - 2²) - 1 = 0

<=> x - 4 - 1 = 0

<=> x = 5

b. 4 - (x - 2)² = 0

<=> 2² - (x - 2)² = 0

<=> (2 - x + 2)(2 + x - 2) = 0

<=> x(4 - x) = 0

<=> \(\left[{}\begin{matrix}x=0\\4-x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=4\end{matrix}\right.\)

d. (3x - 2)² - (2x + 3)² = 5(x + 4)(x - 4)

<=> (3x - 2 - 2x - 3)(3x - 2 + 2x + 3) = 5(x² - 16)

<=> (x - 5)(5x + 1) = 5x² - 80

<=> 5x² + x - 25x - 5 = 5x² - 80

<=> 5x² - 5x² + x - 25x = -80 + 5

<=> -24x = -75

<=> x = \(\dfrac{25}{8}\)

a)\(\left(x-2^2\right)-1=0\Rightarrow x-4-1=0\Rightarrow x=5\)