4 (x-3)=3
x-3=3:4
x-3=0,75
x=0,75+3
x=3,75

b, 4 ( x - 3 ) = 3

x - 3 = \(\dfrac{3}{4}\) = 0,75 

x = 0,75 + 3 = 3,75

x=3:4+3=15/4

Tìm x:

5x + 5 = 150 : 2 + 3

5x + 5 = 75+3

5x + 5 =78

5x=78-5

5x=73

x=73:5

x= 10,46

\(5x+5=150:2+3\)

\(\Leftrightarrow5x+5=75+3=78\)

\(\Leftrightarrow5x=78-5=73\)

\(\Leftrightarrow x=\frac{73}{5}=14,6\)

a: ĐKXĐ: x<>0; x<>1

\(P=\dfrac{x^2-1+x+2-x^2}{x\left(x-1\right)}\cdot\dfrac{x-1}{x}\)

\(=\dfrac{x+1}{x\cdot x}=\dfrac{x+1}{x^2}\)

b: |2x-1|=3

=>2x-1=3 hoặc 2x-1=-3

=>x=-1(nhận) hoặc x=2(nhận)

Khi x=-1 thì \(P=\dfrac{-1+1}{\left(-1\right)^2}=0\)

Khi x=2 thì \(P=\dfrac{2+1}{2^2}=\dfrac{3}{4}\)

\(\dfrac{10^3+5\cdot10^2+5^2}{6^3+3\cdot6^2+3^3}=\dfrac{5^3\cdot2^3+5\cdot2^2\cdot5^2+5^2}{2^3\cdot3^3+3\cdot2^2\cdot3^2+3^3}\\ =\dfrac{5^3\left(2^3+2^2+1\right)}{3^3\left(2^3+2^2+1\right)}=\dfrac{5^3}{3^3}=\dfrac{125}{27}\)

\(a,12\left(x-1\right)=0\\ x-1=0\\ x=1\\ b,45+5\left(x-3\right)=70\\ 5\left(x-3\right)=25\\ x-3=5\\ x=8\\ c,3.x-18:2=12\\ 3.x-9=12\\ 3.x=21\\ x=7\)

12(x-1)=0

     (x-1)=0:12

      x-1=0

      x=0+1

      x= 1

Vậy x= 1

12 ( x - 1 ) = 0
       x - 1   = 0 : 12
       x - 1   = 0
=>   x        = 1