Ta có |x| ≥ 0, nên các câu:

a) |-2,5| = 2,5 đúng

b) |-2,5| = -2,5 sai

c) |-2,5| = -(-2,5) = 2,5 đúng

1,Các khẳng định đúng là :

a,\(|-2,5|=2,5\)Đúng

c,\(|-2,5|=-\left(-2,5\right)\)Đúng

2,Tìm x:

a, \(|x|=\dfrac{1}{5}\Rightarrow x=\dfrac{1}{5}hoặc-\dfrac{1}{5}\)

b, \(|x|=0,37\Rightarrow x=0,37hoặc-0,37\)

c,\(|x|=0\Rightarrow x=0\)

d,\(|x|=1\dfrac{2}{3}\Rightarrow x=1\dfrac{2}{3}hoặc-\left(1\dfrac{2}{3}\right)\)

nhớ like mình nha

Lời giải:

1. Ta có |x| ≥ 0, nên các câu:

a) |-2,5| = 2,5 đúng

b) |-2,5| = -2,5 sai

c) |-2,5| = -(-2,5) = 2,5 đúng

2. Tìm x

a) |x| = => x = ±

b) |x| = 0,37 => x = ± 0,37

c) |x| =0 => x = 0

d) |x| = => x = ±

X

A= (3,1 - 2,5) - (-2,5 + 3,1)

=3.1-2.5+2.5-3.1

=0

B= (5,3 - 2,8) - (4 + 5,3)

=5.3 - 2.8-4-5.3

= -6.8

C= -(251.3 + 281) + 3.251 - (1-281)

=-251.3-281+3.251-1+281

=-1

D= -(3/5+3/4)−(−3/4+2/5)

= -3/5-3/4+3/4-2/5

= -5/5

=-1

\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)=3,1-2,5+2,5-3,1=0\)

\(B=\left(5,3-2,8\right)-\left(4+5,3\right)=5,3-2,8-4-5,3=-6,8\)

\(C=-\left(215\cdot3+281\right)+3\cdot215-\left(1-281\right)=-215\cdot3-281+3\cdot215-1+281=1\)

\(D=-\left(\frac{3}{5}+\frac{3}{4}\right)-\left(-\frac{3}{4}+\frac{2}{5}\right)=-\frac{3}{5}-\frac{3}{4}+\frac{3}{4}-\frac{2}{5}=-1\)

Bài 1 : Tính giá trị của các biểu thức sau đã bỏ dấu ngoặc :

A= (3,1 - 2,5) - (- 2,5 + 3,1) = 3,1 - 2,5 + 2,5 - 3,1 = 0

B= (5,3 - 2,8) - (4 + 5,3) = 5,3 - 2,8 - 4 - 5,3 = - 6,8

C= - (251.3 + 281) + 3.251 - (1 - 281) = - 753 - 281 + 753 + 280 = - 1

D= - (35 + 34) − ( − 34 + 25) = - 35 - 34 + 34 - 25 = - 60

A = (3,1 – 2,5)  – (-2,5 + 3,1) = 3,1 – 2,5 + 2,5 – 3,1 = 0

B  = (5,3 – 2,8) – (4 + 5,3) = 5,3 – 2,8 – 4 – 5,3

A=(3,1-2,5)-(-2,5+3,1)=3,1-2,5+2,5-3,1=0

B=(5,3-2,8)-(4+5,3)=5,3-2,8-4-5,3=-6,8

A = \(\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)

\(=3,1-2,5+2,5-3,1=6,2\)

B = \(\left(5,3-2,8\right)-\left(4+5,3\right)\)

\(=5,3-2,8-4-5,3=-6,8\)

C = \(-\left(251.3+281\right)+3.251-\left(1-281\right)\)

\(=-251.3-281+3.251-1+281=-1\)

D = \(-\left(\frac{3}{5}+\frac{3}{4}\right)-\left(-\frac{3}{4}+\frac{2}{5}\right)\)

\(=-\frac{3}{5}-\frac{3}{4}+\frac{3}{4}-\frac{2}{5}=-1\)

(Nhớ k cho mình với nhá!)

a) (4,1 - 2,5 ) - ( -2,5 + 3,1 ) = 1,6 - 0,6 = 1

b) ( 5,3 - 2,8) - ( 4+ 5,3) = 2,5 - 9,3 = -6.8

c) -( 251,3 + 281) + 3,251 - (1 - 981) = -532,3 + 3,251 + 980 = 450,951

d) -(3/5 + 3/4) - ( -3/4 +2/5) = -3/5 - 3/4 + 3/4 - 2/5 = -1

a) \(0,2 + 2,5:\frac{7}{2} = \frac{2}{{10}} + \frac{25}{10}:\frac{7}{2} = \frac{1}{5} + \frac{25}{10}.\frac{2}{7} \\= \frac{1}{5} + \frac{5}{7} = \frac{7}{{35}} + \frac{{25}}{{35}} = \frac{{32}}{{35}}\)

b)

\(\begin{array}{l}9.{\left( {\frac{{ - 1}}{3}} \right)^2} - {\left( { - 0,1} \right)^3}:\frac{2}{{15}}\\ = 9.\frac{1}{9} - {\left( {\frac{{ - 1}}{{10}}} \right)^3}:\frac{2}{{15}}\\ = 1 - \frac{{ - 1}}{{1000}}:\frac{2}{{15}}\\ = 1 - \frac{{ - 1}}{{1000}}.\frac{{15}}{2}\\ = 1 + \frac{3}{{400}}\\=\frac{400}{400}+\frac{3}{400}\\ = \frac{{403}}{{400}}\end{array}\)

1, 

\(\begin{array}{l}2,5.\left( {4,1 - 3 - 2,5 + 2.7,2} \right) + 4,2:2\\ = 2,5.\left( {4,1 - 3 - 2,5 + 14,4} \right) + 4,2:2\\ = 2,5.\left( {1,1 - 2,5 + 14,4} \right) + 2,1\\ = 2,5.\left( { - 1,4 + 14,4} \right) + 2,1\\ = 2,5.13 + 2,1\\ = 32,5 + 2,1\\ = 34,6\end{array}\)

2, 

Cách 1:

\(\begin{array}{l}2,86.4 + 3,14.4 - 6,01.5 + {3^2}\\ = 11,44 + 12,56 - 30,05 + 9\\ = \left( {11,44 + 12,56} \right) + \left( { - 30,05 + 9} \right)\\ = 24 + \left( { - 21,05} \right)\\ = 24 - 21,05\\ = 2,95\end{array}\)

Cách 2: 

\(\begin{array}{l}2,86.4 + 3,14.4 - 6,01.5 + {3^2}\\ = 4.(2,86+3,14) - 30,05 + 9\\ = 4.6 + \left( { - 30,05 + 9} \right)\\ = 24 + \left( { - 21,05} \right)\\ = 24 - 21,05\\ = 2,95\end{array}\)

\(\Leftrightarrow-\dfrac{8}{17}\left(\dfrac{5}{2}-3x\right)=\dfrac{5}{3}\left(2x+\dfrac{8}{5}\right)\)

\(\Leftrightarrow x\cdot\dfrac{24}{17}-\dfrac{20}{17}=\dfrac{10}{3}x+\dfrac{8}{3}\)

\(\Leftrightarrow x\cdot\dfrac{-98}{51}=\dfrac{196}{51}\)

hay x=-2