(27x3-1) : (3x-1) Tính nhanh nha
Tính nhanh: (27x3 – 1) : (3x – 1)
(27x3 – 1) : (3x – 1)
(Sử dụng HĐT để phân tích số bị chia thành tích)
= [(3x)3 – 1] : (3x – 1)
(Xuất hiện hằng đẳng thức (7))
= (3x – 1).[(3x)2 + 3x.1 + 12] : (3x – 1)
= (3x – 1).(9x2 + 3x + 1) : (3x – 1)
= 9x2 + 3x + 1
Thực hiện phép tính:
a)(x+3).(x-3)-(x-2).(x+5)
b)(27x3+1):(9x2-3x+1)-(3x-19)
a) = x^2 - 9 - (x^2 + 3x - 10)
= -3x + 1
b) = 3x + 1 - 3x + 19
= 20
a: \(\left(x+3\right)\left(x-3\right)-\left(x-2\right)\left(x+5\right)\)
\(=x^2-9-x^2-3x+10\)
\(=-3x+1\)
b: \(\dfrac{27x^3+1}{9x^2-3x+1}-\left(3x-19\right)\)
\(=3x+1-3x+19\)
=20
Cho ( 27 x 3 + 27 x 2 + 9 x + 1 ) : ( 3 x + 1 ) 2 = (…) Điền vào chỗ trống đa thức thích hợp
A. ( 3 x + 1 ) 5
B. 3x + 1
C. 3x – 1
D. ( 3 x + 1 ) 3
Ta có
( 27 x 3 + 27 x 2 + 9 x + 1 ) : ( 3 x + 1 ) 2 = ( 3 x + 1 ) 3 : ( 3 x + 1 ) 2 = 3 x + 1
Đáp án cần chọn là: B
Tìm x:
a) 27x3-27x2+9x-1=\(\dfrac{-1}{8}\)
b) x(4-x)+(2x-1)(x-4)=0
c) 3x(5x-2)-10x+4=0
a.
\(\Leftrightarrow\left(3x-1\right)^3=\left(-\dfrac{1}{2}\right)^3\)
\(\Leftrightarrow3x-1=-\dfrac{1}{2}\)
\(\Leftrightarrow3x=\dfrac{1}{2}\)
\(\Leftrightarrow x=\dfrac{1}{6}\)
b.
\(\Leftrightarrow\left(2x-1\right)\left(x-4\right)-x\left(x-4\right)=0\)
\(\Leftrightarrow\left(x-4\right)\left(2x-1-x\right)=0\)
\(\Leftrightarrow\left(2x-1\right)\left(x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{1}{2}\\\end{matrix}\right.\)
c.
\(\Leftrightarrow3x\left(5x-2\right)-2\left(5x-2\right)=0\)
\(\Leftrightarrow\left(3x-2\right)\left(5x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=\dfrac{2}{5}\end{matrix}\right.\)
Câu 6: (3x – 2)3 có kết quả là
A. 3x3 – 18x2 + 54x – 8
B. 27x3 – 54x2 + 36x – 8
C. 27x3 – 8
D 3x3 – 8
Phân tích các đa thức sau thành nhân tử:
a) 27 x 3 - 54 x 2 y + 36 xy 2 - 8 y 3 ; b) x 3 - 1 + 5 x 2 -5+3x - 3;
c) a 5 +a 4 +a 3 +a 2 +a + 1.
a) ( 3 x - 2 y ) 3 . b) ( x - 1 ) ( x + 3 ) 2 .
thực hiện các phep tính sau:
a)3x3y2 : x2 b) (x5 + 4x3 – 6x2) : 4x2
c)10x3y – 5x2y2 – 25x4y3) : (-5xy) d) (27x3 – y3) : (3x – y)
\(a,=3xy^2\\ b,=\dfrac{1}{4}x^3+x-\dfrac{3}{2}\\ c,=-2x^2+xy+5x^3y^2\\ d,=\left(3x-y\right)\left(9x^2+3xy+y^2\right):\left(3x-y\right)=9x^2+3xy+y^2\)
tìm x, biết :
a) 27x3 -54x2 +36x=8
b) (x+3) (x2 -3x +5)= x2 +3x
a: Ta có: \(27x^3-54x^2+36x=8\)
\(\Leftrightarrow27x^3-54x^2+36x-8=0\)
\(\Leftrightarrow\left(3x-2\right)^3=0\)
\(\Leftrightarrow3x-2=0\)
hay \(x=\dfrac{2}{3}\)
b: Ta có: \(\left(x+3\right)\cdot\left(x^2-3x+5\right)=x^2+3x\)
\(\Leftrightarrow\left(x+3\right)\cdot\left(x^2-4x+5\right)=0\)
\(\Leftrightarrow x=-3\)
Bài 2: Phân tích đa thức sau thành nhân tử:
a) x4 - y4
b) x2 - 3y2
c) (3x - 2y)2 - (2x - 3y)2
d) 9(x - y)2 - 4(x + y)2
e) (4x2 - 4x + 1) - (x + 1)2
f) x3 + 27
g) 27x3 - 0,001
h) 125x3 - 1
a) \(x^4-y^4\)
\(=\left(x^2\right)^2-\left(y^2\right)^2\)
\(=\left(x^2-y^2\right)\left(x^2+y^2\right)\)
\(=\left(x+y\right)\left(x-y\right)\left(x^2+y^2\right)\)
b) \(x^2-3y^2\)
\(=x^2-\left(y\sqrt{3}\right)^2\)
\(=\left(x-y\sqrt{3}\right)\left(x+y\sqrt{3}\right)\)
c) \(\left(3x-2y\right)^2-\left(2x-3y\right)^2\)
\(=\left(3x-2y+2x-3y\right)\left(3x-2y-3x+2y\right)\)
\(=0\cdot0\)
\(=0\)
d) \(9\left(x-y\right)^2-4\left(x+y\right)^2\)
\(=\left(3x-3y\right)^2-\left(2x+2y\right)^2\)
\(=\left(3x-3y-2x-2y\right)\left(3x-3y+2x+2y\right)\)
\(=\left(x-5y\right)\left(5x-y\right)\)
e) \(\left(4x^2-4x+1\right)-\left(x+1\right)^2\)
\(=\left(2x-1\right)^2-\left(x+1\right)^2\)
\(=\left(2x-1+x+1\right)\left(2x-1-x-1\right)\)
\(=3x\left(x-2\right)\)
f) \(x^3+27\)
\(=x^3+3^3\)
\(=\left(x+3\right)\left(x^2-3x+9\right)\)
g) \(27x^3-0,001\)
\(=\left(3x\right)^3-\left(0,1\right)^3\)
\(=\left(3x-0,1\right)\left(9x^2+0,3x+0,01\right)\)
h) \(125x^3-1\)
\(=\left(5x\right)^3-1^3\)
\(=\left(5x-1\right)\left(25x^2+5x+1\right)\)