Question

(27x³-1) : (3x-1) Tính nhanh nha

Answer 1

Làm thế này nha

\(\frac{27x^3-1}{3x-1}=\frac{\left(3x\right)^3-1}{3x-1}=\frac{\left(3x-1\right)\left(9x^2+3x+1\right)}{3x-1}=9x^2+3x+1\)

Answer 2

Ta có: \(\left(27x^3-1\right):\left(3x-1\right)=\left[\left(3x\right)^3-1^3\right]:\left(3x-1\right)=\left(3x-1\right)\left(9x^2+3x+1\right):\left(3x-1\right)=9x^2+3x+1\)

Answer 3

(27x^3-1) : (3x-1)

= ( 3x - 1)(9x^2+ 3x + 1 ): ( 3x - 1)

= 9x^2 + 3x + 1