B=\(\frac{\frac{5}{22}+\frac{3}{13}-\frac{1}{2}}{\frac{4}{13}-\frac{2}{11}+\frac{3}{2}}\)
Tính: a) \(\frac{4}{{ - 3}} + \frac{{ - 22}}{5}\)
b) \(\frac{{ - 5}}{{ - 6}} + \frac{7}{{ - 8}}\).
a)
\(\begin{array}{l}\frac{4}{{ - 3}} + \frac{{ - 22}}{5} =\frac{-4}{{3}} + \frac{{ - 22}}{5}= \frac{{-4.5}}{{3.5}} + \frac{{ - 22.3}}{{5.3}}\\ = \frac{{-20}}{{15}} + \frac{{-66}}{{15}} = \frac{{ - 86}}{{ 15}}\end{array}\)
b)
\(\begin{array}{l}\frac{{ - 5}}{{ - 6}} + \frac{7}{{ - 8}} = \frac{{5}}{{6}} + \frac{-7}{{8}}= \frac{{5.4}}{{6.4}} + \frac{{-7.3}}{{8.3}}\\ = \frac{{20}}{{24}} + \frac{{-21}}{{24}} = \frac{-1}{{24}}\end{array}\).
Tính nhanh: \(\frac{-5}{11}+\frac{7}{22}-\frac{-4}{33}-\frac{5}{44}=38\frac{1}{22}-39\frac{7}{22}\)
Tính hợp lí
a,
\(A=\left(-\frac{5}{11}+\frac{7}{22}-\frac{4}{33}-\frac{5}{44}\right).\left(\frac{837}{22}-\frac{865}{22}\right)\)
b, \(B=1-\frac{1}{1+\frac{2}{3-\frac{4}{5-7}}}\)
c, \(C=-\frac{1}{10}-\frac{1}{100}-\frac{1}{1000}-\frac{1}{10000}-\frac{1}{100000}\)
Chứng minh:
\(\frac{7}{12}
gọi A=1/21+1/22+1/23+...+1/40
chia A thành 2 nhóm A1 và A2( A1+A2=A)
ta có A1=1/21+1/22+1/23+...+1/30>1/30+1/30+1/30+...+1/30(có 10 phân số 1/30)
A1>10/30=1/3(1)
ta có A2=1/31+1/32+1/33+...+1/40>1/40+1/40+1/40+...+1/40(có 10 phân số 1/40)
A2>10/40=1/4(2)
từ (1)và (2) suy ra
A1+A2>1/3+1/4
A>7/12(3)
ta có A1=1/21+1/22+1/23+...+1/20<1/20+1/20+1/20+...+1/20(có 10 phân số 1/20)
A1<10/20=1/2(4)
ta có A2=1/31+1/32+1/33+...+1/40<1/30+1/30+1/30+...+1/30(có 10 phân số 1/30)
A2<10/30=1/3(5)
từ (4)và (5) suy ra
A1+A2<1/2+1/3
A<5/6(6)
từ (3),(6) suy ra 7/12<1/21+1/22+1/23+...+1/40<5/6
cái A1+1/21+1/22+1/23+1/24+1/25+...+1/30<1/20+1/20+1/20+1/20+...+1/20 nhé
1 tính
b)\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
Tính giá trị của các biểu thức sau:
\(\begin{array}{l}a)\left( {\frac{2}{3} + \frac{1}{6}} \right):\frac{5}{4} + \left( {\frac{1}{4} + \frac{3}{8}} \right):\frac{5}{2}\\b)\frac{5}{9}:\left( {\frac{1}{{11}} - \frac{5}{{22}}} \right) + \frac{7}{4}.\left( {\frac{1}{{14}} - \frac{2}{7}} \right)\end{array}\)
\(\begin{array}{l}a)\left( {\frac{2}{3} + \frac{1}{6}} \right):\frac{5}{4} + \left( {\frac{1}{4} + \frac{3}{8}} \right):\frac{5}{2}\\ = \left( {\frac{4}{6} + \frac{1}{6}} \right).\frac{4}{5} + \left( {\frac{2}{8} + \frac{3}{8}} \right).\frac{2}{5}\\ = \frac{5}{6}.\frac{4}{5} + \frac{5}{8}.\frac{2}{5}\\ = \frac{2}{3} + \frac{1}{4}\\ = \frac{8}{{12}} + \frac{3}{{12}}\\ = \frac{{11}}{{12}}\\b)\frac{5}{9}:\left( {\frac{1}{{11}} - \frac{5}{{22}}} \right) + \frac{7}{4}.\left( {\frac{1}{{14}} - \frac{2}{7}} \right)\\ = \frac{5}{9}:\left( {\frac{2}{{22}} - \frac{5}{{22}}} \right) + \frac{7}{4}.\left( {\frac{1}{{14}} - \frac{4}{{14}}} \right)\\ = \frac{5}{9}:\frac{{ - 3}}{{22}} + \frac{7}{4}.\frac{{ - 3}}{{14}}\\ = \frac{5}{9}.\frac{{ - 22}}{3} + \frac{{ - 3}}{8}\\ = \frac{{ - 110}}{{27}} + \frac{{ - 3}}{8}\\ = \frac{{ - 880}}{{216}} + \frac{{ - 81}}{{216}}\\ = \frac{{ - 961}}{{216}}\end{array}\)
\(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
\(=\frac{5}{9}:\left(\frac{-3}{22}\right)+\frac{5}{9}:\left(-\frac{3}{5}\right)\)
\(=\frac{5}{9}.\left(\frac{-22}{3}\right)+\frac{5}{9}.\left(-\frac{5}{3}\right)\)
\(=-\frac{110}{27}+-\frac{25}{27}\)
\(=-5\)
Em làm thế đúng không các anh chị?
đúng đó nhưng bạn nên nhóm \(\frac{-22}{3}\)và \(\frac{-5}{3}\)vào với nhau và đặt \(\frac{5}{9}\)ra ngoài sẽ tính nhanh hơn
a.\(\left(\frac{-2}{3}+\frac{3}{7}\right):\frac{4}{5}+\left(\frac{-1}{3}+\frac{4}{7}\right):\frac{4}{5}\)
b. \(\frac{5}{9}:\left(\frac{1}{11}-\frac{5}{22}\right)+\frac{5}{9}:\left(\frac{1}{15}-\frac{2}{3}\right)\)
a,\(\left\{\frac{2}{3}\right\}^3-\left\{\frac{3}{4}\right\}^2.\left\{-1\right\}^5\)
b,\(12:\left\{\frac{3}{4}-\frac{5}{6}\right\}^2\)
c,\(\frac{7}{22}:\frac{3}{11}+\frac{7}{22}:\frac{4}{11}\)
d,\(\frac{12}{35}.\left\{\frac{7}{4}+\frac{13}{4}\right\}-\frac{1}{3}\)
a. \(\left(\frac{2}{3}\right)^3-\left(\frac{3}{4}\right)^2.\left(-1\right)^5=\frac{8}{27}-\frac{9}{16}.\left(-1\right)=\frac{8}{27}+\frac{9}{16}=\frac{371}{432}\)
b. \(12:\left(\frac{3}{4}-\frac{5}{6}\right)^2=12:\left(-\frac{1}{12}\right)^2=12:\frac{1}{144}=12.144=1728\)
c. \(\frac{7}{22}:\frac{3}{11}+\frac{7}{22}:\frac{4}{11}=\frac{7}{22}.\frac{11}{3}+\frac{7}{22}.\frac{11}{4}=\frac{7}{22}\left(\frac{11}{3}+\frac{11}{4}\right)\)
\(=\frac{7}{22}.\frac{77}{12}=\frac{49}{24}\)
d. \(\frac{12}{35}\left(\frac{7}{4}+\frac{13}{4}\right)-\frac{1}{3}=\frac{12}{35}.5-\frac{1}{3}=\frac{12}{7}-\frac{1}{3}=\frac{29}{21}\)