=>x:3=472

hay x=1416

có ai lm đc bài này khum giúp mọi vs

1000-(x:3)=528 

x:3=1000-528

x:3=472

x=472x3

x=1416

\(\Rightarrow\dfrac{x}{8}=\dfrac{y}{6}=\dfrac{z}{11}=k\)

\(\Rightarrow\left\{{}\begin{matrix}x=8k\\y=6k\\z=11k\end{matrix}\right.\)\(\Rightarrow xyz=528k^3=-528\Rightarrow k=-1\)

\(\Rightarrow\left\{{}\begin{matrix}x=8.\left(-1\right)=-8\\y=6.\left(-1\right)=-6\\z=11.\left(-1\right)=-11\end{matrix}\right.\)

a) \(2^x+124=5^7\)

\(2^x=78125-124\)

\(2^x=78001\)

b) \(10^x+528=7^2\)

\(10^x=49-528\)

\(10^x=-479\)

     \(528+216\div2\times3\)

\(=528+108\times3\)

\(=528+324\)

\(=852\)

528 + 216 : 2 x 3 

=528 + 36

= 564 

528 + 216 ÷ 2 × 3

= 528 + 108 × 3

= 528 + 324

= 852

🖤🖤🖤

Ta có: \(\frac{x}{4}=\frac{y}{3}\Rightarrow\frac{x}{8}=\frac{y}{6}\)

=> \(\frac{x}{8}=\frac{y}{6}=\frac{z}{11}\)

Đặt k = \(\frac{x}{8}=\frac{y}{6}=\frac{z}{11}\) 

=> \(\begin{cases}x=8k\\y=6k\\z=11k\end{cases}\)

Mà x.y.z = -528 => 8k.6k.11k = 528k³ = -528

=> k³ = -1 

=> k =-1

=> \(\begin{cases}x=-8\\y=-6\\z=-11\end{cases}\)