N=30,75+\(\frac{1}{12}\)+3\(\frac{1}{6}\)
Tính:
\(\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}\)
\(\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}=\frac{\left(\frac{121}{200}+\frac{83}{200}\right):\frac{1}{100}}{\frac{1}{12}-\frac{149}{4}+\frac{19}{6}}=\frac{\frac{51}{50}.100}{\frac{1}{12}-\frac{447}{12}+\frac{38}{12}}\)
=\(\frac{102}{-34}=-3\)
Tính :
\(\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}\)
\(B=\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}\)
Giúp mik nha!!!
Ta có : \(B=\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}\)
\(=>B=\frac{\left(\frac{121}{200}+\frac{415}{1000}\right):\frac{1}{100}}{\frac{1}{12}-\frac{3725}{100}+\frac{19}{6}}\)
\(=>B=\frac{\left(\frac{121}{200}+\frac{83}{200}\right)\cdot100}{\frac{1}{12}-\frac{149}{4}+\frac{19}{6}}\)
\(=>B=\frac{\frac{204}{200}\cdot100}{\frac{1}{12}-\frac{447}{12}+\frac{38}{12}}\)
\(=>B=\frac{\frac{204\cdot100}{200}}{-\frac{408}{12}}=\frac{\frac{204}{2}}{-34}=\frac{102}{-34}=-3\)
bạn biết bấm máy tính không :v
nó bằng : -3
Tìm x biết:
(1/12+19/6-30,75).x-8=(3/5+0,415+1/200);0,01
Câu 1 Tim số nguyên x, biet rằng
\(4\frac{1}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)\le\times\le\frac{2}{3}.\left(\frac{1}{2}-\frac{1}{2}-\frac{3}{4}\right)\)
Câu 2 : Tính
\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)
Câu 3 ; Tìm x Biet
\(\left(\frac{1}{12}+3\frac{1}{6}-30,75\right).\times-8=\left(\frac{3}{5}+0,415+\frac{1}{200}\right):0,01\)
Câu 4 : So Sánh \(A=\frac{10^8+2}{10^8-1}\);
Câu 2 :
\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)
\(\frac{28}{15}.\frac{3}{4}-\left(\frac{104}{195}+\frac{25}{100}\right).\frac{24}{47}-\frac{51}{13}:3\)
\(\frac{28}{15}.\frac{3}{4}-\frac{47}{60}.\frac{24}{47}-\frac{51}{13}:3\)
\(\frac{7}{5}-\frac{2}{5}-\frac{51}{13}.\frac{1}{3}\)
\(\frac{7}{5}-\frac{2}{5}-\frac{17}{13}\)
\(-\frac{4}{13}\)
Câu 1:
\(-\frac{13}{9}\le x\le-\frac{1}{2}\)
\(x=-1\)
AI GIÚP TỚ VỚI!!!
A) TÌM X
1) \(\left(\frac{1}{12}+3\frac{1}{6}-30,75\right).x-8=\left(\frac{3}{5}+0,415+\frac{1}{200}\right):0,01\)
2) \(\left(\frac{1}{1.101}+\frac{1}{2.102}+...+\frac{1}{10.110}\right).x=\frac{1}{1.11}+\frac{1}{2.12}+...+\frac{1}{100.110}\)
B) CHO:
\(M=\frac{1}{11}+\frac{1}{12}+\frac{1}{13}+...+\frac{1}{19}+\frac{1}{20}\); \(N=\frac{5^2}{5.10}+\frac{5^2}{10.15}+...+\frac{5^2}{2000.2005}+\frac{5^2}{2005.2010}\)
a) Tính tổng M
b) So sánh M và N
C) CHỨNG TỎ RẰNG
a)\(S=\frac{1}{5}+\frac{1}{13}+\frac{1}{14}+\frac{1}{15}+\frac{1}{61}+\frac{1}{62}+\frac{1}{63}< \frac{1}{2}\)
(1/12+3 1/6-30,75).x -8 = (3/5+0,415+1/200):0,01
(1/12+19/6-123/4).x-8=(3/5+83/200+1/200):1/100
-55/2.x-8=51/50:1/100
-55/2.x-8=102
-55/2.x=102+8=110
x=110:-55/2=-4
Tìm x
a,(4x-5).(\(\dfrac{5}{4}\)x-2)=0 b,(\(\dfrac{1}{12}\)+\(3\dfrac{1}{6}\)-30,75)x-8=(\(\dfrac{3}{5}\)+0,415+\(\dfrac{1}{200}\)):0,01
a: =>4x-5=0 hoặc 5/4x-2=0
=>x=5/4 hoặc x=2:5/4=2*4/5=8/5
b: =>(1/12+19/6-30,75)*x-8=102
=>-55/2x=110
=>x=-4
Tính:
\(\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}\)
AI LÀM XONG NHANH NHẤT MÌNH SẼ TÍCH CHO 3 CÁIIIIIIIIIII....!
AI GIÚP MÌNH ĐIIIII...........!MÌNH CẦN GẤP LẮM
Ta có: \(\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}=\frac{\left(\frac{121}{200}+\frac{19}{40}\right).100}{\frac{1}{12}-\frac{149}{4}+\frac{17}{6}}\)
\(=\frac{108}{-\frac{103}{3}}=-\frac{324}{103}\)
tìm x biết
(1/2+19/6-30,75).x-8=(3/5+0,415+1/200):0,01
\(\left(\dfrac{1}{2}+\dfrac{19}{6}-30,75\right).x-8=\left(\dfrac{3}{5}+0,415+\dfrac{1}{200}\right):0.01\)
\(\left(\dfrac{1}{2}+\dfrac{19}{6}-\dfrac{123}{4}\right).x-8=\left(\dfrac{3}{5}+\dfrac{83}{200}+\dfrac{1}{200}\right):\dfrac{1}{100}\)
\(\dfrac{-325}{12}.x-8=\dfrac{51}{50}:\dfrac{1}{100}\)
\(\dfrac{-325}{12}.x-8=102\)
\(\dfrac{-325}{12}.x=102+8\)
\(\dfrac{-325}{12}.x=110\)
\(x=110:\dfrac{-325}{12}\)
\(x=\dfrac{-264}{65}\)