Ta có : \(B=\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}\)
\(=>B=\frac{\left(\frac{121}{200}+\frac{415}{1000}\right):\frac{1}{100}}{\frac{1}{12}-\frac{3725}{100}+\frac{19}{6}}\)
\(=>B=\frac{\left(\frac{121}{200}+\frac{83}{200}\right)\cdot100}{\frac{1}{12}-\frac{149}{4}+\frac{19}{6}}\)
\(=>B=\frac{\frac{204}{200}\cdot100}{\frac{1}{12}-\frac{447}{12}+\frac{38}{12}}\)
\(=>B=\frac{\frac{204\cdot100}{200}}{-\frac{408}{12}}=\frac{\frac{204}{2}}{-34}=\frac{102}{-34}=-3\)
bạn biết bấm máy tính không :v
nó bằng : -3