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Tiến Nguyễn Văn
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Nguyễn Châu Mỹ Linh
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Hatsune Miku
19 tháng 6 2018 lúc 15:39
​29/152323/125/65/4-31/1231/6-13/31087/1801/61/62-67/24
Phí Nhật Minh
11 tháng 4 2022 lúc 16:57
Ôi mẹ ơi dài khiếp
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Nguyễn Châu Mỹ Linh
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Nguyen Thi Thanh Thao
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Đặng Tiến Pháp
29 tháng 9 2016 lúc 13:27

A = (1 - 2/3 + 4/3) - (4/5 - 1) + (7/5 + 2)

A= (3/3 - 2/3 + 4/3) - (4/5 - 5/5) + (7/5 + 10/5)

A= 5/3 + 1/5 + 17/5

A= 5/3 +18/5

A= 25/15 + 54/15

A= 79/15

B= (-3 + 3/4 - 1/3 ) : (5 + 2/5 - 2/3)

B= (-36/12 + 9/12 - 4/12) : (75/15 + 6/15 - 10/15)

B= -31/12 : 71/15

B= -155/284

C= (3/5 - 4/5 ) . (2/7 - 3/14) - (5/9 - 7/27) . (1 - 3/5) + (1 - 11/12) . (1-11/12)

C= -1/5 . 1/14 - 8/27 . 2/5 + 1/12 . 1/12

C=-1/70 - 16/135 + 1/144

C=-216/15120 - 1792/15120 + 105/15120

C=-1903/15120

Phí Quỳnh Anh
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Phạm Aley
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Thành Lê
2 tháng 11 2016 lúc 13:54

A=\(-\frac{155}{284}\)

B=\(-\frac{43}{3780}\)

nguyen ngoc son
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Nguyễn Lê Phước Thịnh
2 tháng 7 2020 lúc 10:08

Bài 1:

a) Ta có: \(25\cdot\left(\frac{-1}{5}\right)^3+\frac{1}{5}-2\cdot\left(\frac{-1}{2}\right)^2-\frac{1}{2}\)

\(=25\cdot\frac{-1}{125}+\frac{1}{5}-2\cdot\frac{1}{4}-\frac{1}{2}\)

\(=-\frac{1}{5}+\frac{1}{5}-\frac{1}{2}-\frac{1}{2}\)

\(=\frac{-2}{2}=-1\)

b) Ta có: \(35\frac{1}{6}:\left(\frac{-4}{5}\right)-46\frac{1}{6}:\left(\frac{-4}{5}\right)\)

\(=\frac{211}{6}\cdot\frac{-5}{4}-\frac{277}{6}\cdot\frac{-5}{4}\)

\(=\frac{-5}{4}\cdot\left(\frac{211}{6}-\frac{277}{6}\right)\)

\(=\frac{-5}{4}\cdot\left(-11\right)=\frac{55}{4}\)

c) Ta có: \(\left(\frac{-3}{4}+\frac{2}{5}\right):\frac{3}{7}+\left(\frac{3}{5}+\frac{-1}{4}\right):\frac{3}{7}\)

\(=\frac{-7}{20}\cdot\frac{7}{3}+\frac{7}{20}\cdot\frac{7}{3}\)

\(=\frac{7}{3}\cdot\left(-\frac{7}{20}+\frac{7}{20}\right)=\frac{7}{3}\cdot0=0\)

d) Ta có: \(\frac{7}{8}:\left(\frac{2}{9}-\frac{1}{18}\right)+\frac{7}{8}\cdot\left(\frac{1}{36}-\frac{5}{12}\right)\)

\(=\frac{7}{8}\cdot6+\frac{7}{8}\cdot\frac{-7}{18}\)

\(=\frac{7}{8}\cdot\left(6+\frac{-7}{18}\right)\)

\(=\frac{7}{8}\cdot\frac{101}{18}=\frac{707}{144}\)

e) Ta có: \(\frac{1}{6}+\frac{5}{6}\cdot\frac{3}{2}-\frac{3}{2}+1\)

\(=\frac{1}{6}+\frac{15}{12}-\frac{3}{2}+1\)

\(=\frac{2}{12}+\frac{15}{12}-\frac{18}{12}+\frac{12}{12}\)

\(=\frac{11}{12}\)

f) Ta có: \(\left(-0,75-\frac{1}{4}\right):\left(-5\right)+\frac{1}{15}-\left(-\frac{1}{5}\right):\left(-3\right)\)

\(=\left(-1\right):\left(-5\right)+\frac{1}{15}-\frac{1}{15}\)

\(=\frac{1}{5}\)

Phương Thảo Nguyễn
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Lê Trang
7 tháng 8 2020 lúc 21:13

a) \(\left(\frac{11}{12}:\frac{44}{16}\right).\left(\frac{-1}{3}+\frac{1}{2}\right)\) \(=\left(\frac{11}{12}.\frac{16}{44}\right).\left(\frac{-2}{6}+\frac{3}{6}\right)\) \(=\frac{1}{3}.\frac{1}{6}\) \(=\frac{1}{18}\)

b) \(\frac{\left(-5\right)^2.\left(-5\right)^3.16}{5^4.\left(-2\right)^4}\) \(=\frac{\left(-5\right)^5.2^4}{5^4.\left(-2\right)^4}\) \(=5\) (Có sửa đề lại, nếu có sai thì ib mình sửa lại nhé!)

c) \(7,5:\left(\frac{-5}{3}\right)+2\frac{1}{2}:\left(\frac{-5}{3}\right)\) \(=\frac{15}{2}.\left(\frac{-3}{5}\right)+\frac{5}{2}.\left(\frac{-3}{5}\right)\) \(=\frac{-3}{5}.\left(\frac{15}{2}+\frac{5}{2}\right)\)

\(=\frac{-3}{5}.10\) \(=-6\)

d) \(\left(\frac{-1}{2}+\frac{1}{3}\right).\frac{4}{5}+\left(\frac{2}{3}+\frac{1}{2}\right):\frac{5}{4}\) \(=\left(\frac{-1}{2}+\frac{1}{3}\right).\frac{4}{5}+\left(\frac{2}{3}+\frac{1}{2}\right).\frac{4}{5}\)

\(=\frac{4}{5}.\left(\frac{-1}{2}+\frac{1}{3}+\frac{2}{3}+\frac{1}{2}\right)\) \(=\frac{4}{5}.\left(\frac{0}{2}+1\right)\) \(=\frac{4}{5}.1=\frac{4}{5}\)

lưu hoàng gia bảo
8 tháng 12 2022 lúc 10:44

a) (1112:4416).(−13+12)(1112:4416).(−13+12) =(1112.1644).(−26+36)=(1112.1644).(−26+36) =13.16=13.16 =118=118

b) (−5)2.(−5)3.1654.(−2)4(−5)2.(−5)3.1654.(−2)4 =(−5)5.2454.(−2)4=(−5)5.2454.(−2)4 =5=

c) 7,5:(−53)+212:(−53)7,5:(−53)+212:(−53) =152.(−35)+52.(−35)=152.(−35)+52.(−35) =−35.(152+52)=−35.(152+52)

=−35.10=−35.10 =−6=−6

d) (−12+13).45+(23+12):54(−12+13).45+(23+12):54 =(−12+13).45+(23+12).45=(−12+13).45+(23+12).45

=45.(−12+13+23+12)=45.(−12+13+23+12) =45.(02+1)=45.(02+1) =45.1=45

Quoc Tran Anh Le
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Hà Quang Minh
16 tháng 9 2023 lúc 17:16

a)

\(\begin{array}{l}\frac{1}{9} - 0,3.\frac{5}{9} + \frac{1}{3}\\ = \frac{1}{9} - \frac{3}{{10}}.\frac{5}{9} + \frac{1}{3}\\ = \frac{1}{9} - \frac{3}{{2.5}}.\frac{5}{{3.3}} + \frac{1}{3}\\ = \frac{1}{9} - \frac{1}{6} + \frac{1}{3}\\ = \frac{2}{{18}} - \frac{3}{{18}} + \frac{6}{{18}}\\ = \frac{5}{{18}}\end{array}\)

b)

\(\begin{array}{l}{\left( {\frac{{ - 2}}{3}} \right)^2} + \frac{1}{6} - {\left( { - 0,5} \right)^3}\\ = \frac{4}{9} + \frac{1}{6} - \left( {\frac{{ - 1}}{2}} \right)^3\\  = \frac{4}{9} + \frac{1}{6} - \left( {\frac{{ - 1}}{8}} \right)\\ = \frac{4}{9} + \frac{1}{6} + \frac{1}{8}\\ = \frac{{32}}{{72}} + \frac{{12}}{{72}} + \frac{9}{{72}}\\ = \frac{{53}}{{72}}\end{array}\)