Tính giá trị của biểu thức sau:
a.\(2^4.5-\left[131-\left(13-4^2\right)\right]\)
b.\(\frac{-3}{5}+\frac{28.43}{5.56}+\frac{28.5}{5.24}-\frac{28.21}{5.63}\)
a) 2^4.5-[131-(13-4)^2]
b)-3/5+28.43/5.56+28.5/5.24-28.21/5.63
TÍNH GIÁ TRỊ BIỂU THỨC
\(\frac{-3}{5}\)+\(\frac{28.43}{5.56}\)+\(\frac{28.5}{5.24}\)-\(\frac{28.21}{5.63}\)
\(\frac{-3}{5}+\frac{28.43}{5.56}+\frac{28.5}{5.24}-\frac{28.21}{5.63}\)
=\(\frac{-3}{5}+\frac{2.2.7.43}{5.2.2.7.2}+\frac{2.2.7.5}{2.2.2.3.5}-\frac{2.2.7.3.7}{5.7.3.3}\)
=\(\frac{-3}{5}+\frac{43}{5.2}+\frac{7}{2.3}-\frac{28}{15}\)
=\(\frac{-3}{5}+\frac{43}{10}+\frac{7}{6}-\frac{28}{15}\)
=\(\frac{-18}{30}+\frac{129}{30}+\frac{35}{30}-\frac{56}{30}\)
=\(\frac{-18+129+35-56}{30}\)
=\(\frac{90}{30}=3\)
Chúc bn học tốt
tự làm đê đồ đầu đất
Tinhs pheps tinhs sau :
B = \(-\dfrac{3}{5}+\dfrac{28.43}{5.56}+\dfrac{28.5}{5.24}-\dfrac{28.21}{5.63}\)
\(\dfrac{-3}{5}+\dfrac{43}{10}+\dfrac{7}{6}-\dfrac{28}{15}\)
\(=3\)
giúp tôi với:
-3/5+28.43/5.56+28.5/5.24-28.21/5.63
\(\frac{-3}{5}+\frac{28.43}{5.56}+\frac{28.5}{3.24}-\frac{28.21}{5.63}\)
b)
mk nghĩ bn nê thử tách 28.43/5.56 và 28.21/5.63 ra thành 28/5.43/56 và 28/5.21/63 để có phân số chung, mk sợ sai nên bn cứ thử lm r tự tính tiếp nha
Tính : \(\frac{-3}{5}\)+ \(\frac{28.43}{5.56}\)+ \(\frac{28.5}{5.24}\)- \(\frac{28.21}{5.63}\)
-3/5 + 28.43/5.56 + 28.5/5.24 - 28.21/5.63
=-3/5 + 28.43/5.28.2 + 4.7.5/5.4.6 - 28.21/5.3.21
=-3/5 + 43/10 + 7/6 - 28/15
=-18/30 + 129/30 + 35/30 - 56/30
=-12+129+35-56/30
=94/30=47/15
Tính giá trị các biểu thức sau:
a) \({\left( {\frac{3}{4}} \right)^{ - 2}}{.3^2}{.12^0}\);
b) \({\left( {\frac{1}{{12}}} \right)^{ - 1}}.{\left( {\frac{2}{3}} \right)^{ - 2}}\);
c) \({\left( {{2^{ - 2}}{{.5}^2}} \right)^{ - 2}}:\left( {{{5.5}^{ - 5}}} \right)\).
a) \(\left(\dfrac{3}{4}\right)^{-2}\cdot3^2\cdot12^0=16\)
b) \(\left(\dfrac{1}{12}\right)^{-1}\cdot\left(\dfrac{2}{3}\right)^{-2}=27\)
c) \(\left(2^{-2}\cdot5^2\right)^{-2}:\left(5\cdot5^{-5}\right)=16\)
Tính giá trị của mỗi biểu thức sau:
a) \(\left( {0,25 - \frac{5}{6}} \right).1,6 + \frac{{ - 1}}{3}\)
b) \(3 - 2.\left[ {0,5 + \left( {0,25 - \frac{1}{6}} \right)} \right]\)
a)
\(\begin{array}{l}\left( {0,25 - \frac{5}{6}} \right).1,6 + \frac{{ - 1}}{3}\\ =(\frac{25}{100}-\frac{5}{6}).\frac{16}{10}+\frac{-1}{3}\\= \left( {\frac{1}{4} - \frac{5}{6}} \right).\frac{8}{5} + \frac{{ - 1}}{3}\\ = \left( {\frac{6}{{24}} - \frac{{20}}{{24}}} \right).\frac{8}{5} + \frac{{ - 1}}{3}\\ = \frac{{ - 14}}{{24}}.\frac{8}{5} + \frac{{ - 1}}{3}\\ = \frac{{ - 14}}{{15}} + \frac{{ - 1}}{3}\\ = \frac{{ - 14}}{{15}} + \frac{{ - 5}}{{15}}\\ = \frac{{ - 19}}{{15}}\end{array}\)
b)
\(\begin{array}{l}3 - 2.\left[ {0,5 + \left( {0,25 - \frac{1}{6}} \right)} \right]\\ = 3 - 2.\left[ {\frac{1}{2} + \left( {\frac{1}{4} - \frac{1}{6}} \right)} \right]\\ = 3 - 2.\left( {\frac{1}{2} + \frac{1}{{12}}} \right)\\ =3-2.(\frac{6}{12}+\frac{1}{12})\\= 3 - 2.\frac{7}{{12}}\\ = 3 - \frac{7}{6}\\=\frac{18}{6}-\frac{7}{6}\\ = \frac{{11}}{6}\end{array}\)
Tính giá trị các biểu thức sau:
a) \({\left( { - 5} \right)^{ - 1}}\);
b) \({2^0}.{\left( {\frac{1}{2}} \right)^{ - 5}}\);
c) \({6^{ - 2}}.{\left( {\frac{1}{3}} \right)^{ - 3}}:{2^{ - 2}}\).
a) \(\left(-5\right)^{-1}=-\dfrac{1}{5}\)
b) \(2^0\cdot\left(\dfrac{1}{2}\right)^{-5}=1\cdot32=32\)
c) \(6^{-2}\cdot\left(\dfrac{1}{3}\right)^{-3}:2^{-2}\)
\(=\dfrac{1}{36}\cdot27:\dfrac{1}{4}\)
\(=\dfrac{27\cdot4}{36}=3\)