\(\frac{3x}{x-3}-\frac{x-3}{x+3}=2\left(đkxđ:x\ne\pm3\right)\)
\(< =>\frac{3x\left(x-3\right)-\left(x-3\right)^2}{\left(x-3\right)^2}=2\)
\(< =>\frac{3x\left(x-3\right)}{\left(x-3\right)^2}=2-\frac{\left(x-3\right)^2}{\left(x-3\right)^2}=1\)
\(< =>3x\left(x-3\right)=\left(x-3\right)^2\)
\(< =>3x=x-3\)
\(< =>3x-x=-3\)
\(< =>x=-\frac{3}{2}\left(tmđk\right)\)