Bài làm
\(\frac{3}{2x-1}+1=\frac{2x-1}{2x+1}\) đkxđ: x khác 1/2, x khác -1/2
\(\Leftrightarrow\frac{3\left(2x+1\right)}{\left(2x-1\right)\left(2x+1\right)}+\frac{\left(2x-1\right)\left(2x+1\right)}{\left(2x-1\right)\left(2x+1\right)}=\frac{\left(2x-1\right)^2}{\left(2x-1\right)\left(2x+1\right)}\)
\(\Rightarrow6x+3+4x^2-1=4x^2-4x+1\)
\(\Leftrightarrow4x^2-4x^2+6x+4x=1+1-3\)
\(\Leftrightarrow10x=-1\)
\(\Leftrightarrow x=-\frac{1}{10}\)
Vậy x = -1/10 là nghiệm phương trình
\(\frac{3}{2x-1}+1=\frac{2x-1}{2x+1}\\ =>\frac{3+2x-1}{2x-1}=\frac{2x-1}{2x+1}\\ =>\frac{2x+2}{2x-1}=\frac{2x-1}{2x+1}\\ =>\left(2x+2\right).\left(2x+1\right)=\left(2x-1\right).\left(2x-1\right)\\ =>4x^2+4x+2x+2=4x^2-2x-2x+1\)
=>4x+2x+2x+2x=1-2
=>10x=-1
=>x=-1/10
