\(\left[6+\left(\frac{1}{2}\right)^3-\left|-\frac{1}{2}\right|\right]:\frac{3}{12}\\ =\left[6+\frac{1}{8}-\frac{1}{2}\right]:\frac{1}{4}\\ =\left[\frac{48}{8}+\frac{1}{8}-\frac{4}{8}\right]\cdot4\\ =\frac{45}{8}\cdot4\\ =\frac{45}{2}\)
\([6\) + (\(\frac{1}{2}\))\(^3\) \(-\) \(\left|-\frac{1}{2}\right|\)\(]\) \(:\) \(\frac{3}{12}\)
\(=\) \([6\) + \(\frac{1}{8}\)\(-\)\(\frac{1}{2}]\) \(:\) \(\frac{1}{4}\)
\(=[\frac{48}{8}+\frac{1}{8}-\frac{4}{8}]\)\(:\frac{1}{4}\)
\(=\frac{45}{8}:\frac{1}{4}\)
\(=\frac{45}{8}.4\)
\(=\frac{45}{2}\)