b) \(\left(\frac{7}{2}+2x\right).2\frac{2}{3}=5\frac{1}{3}\)
\(\Rightarrow\frac{7}{2}+2x=5\frac{1}{3}:2\frac{2}{3}\)
\(\Rightarrow\) \(\frac{7}{2}+2x\) \(=2\)
\(\Rightarrow2x=2-\frac{7}{2}\)
\(\Rightarrow2x=-\frac{3}{2}\)
\(\Rightarrow x=-\frac{3}{4}\)
Vậy \(x=-\frac{3}{4}\)
a) \(\frac{2}{3}x-\frac{2}{3}=\frac{5}{12}\)
\(\Rightarrow\)\(\frac{2}{3}x=\frac{5}{12}+\frac{2}{3}\)
\(\Rightarrow\)\(\frac{2}{3}x=\frac{13}{12}\)
\(\Rightarrow\) \(x=\frac{13}{8}\)
Vậy \(x=\frac{13}{8}\)
\(a,\frac{2}{3}x-\frac{2}{3}=\frac{5}{12}\)
\(\frac{2}{3}x=\frac{5}{12}+\frac{2}{3}\)
\(\frac{2}{3}x=\frac{5}{12}+\frac{8}{12}\)
\(x=\frac{13}{12}:\frac{2}{3}\)
\(x=\frac{13}{8}\)
\(b,\left(\frac{7}{2}+2x\right)\cdot2\frac{2}{3}=5\frac{1}{3}\)
\(\left(\frac{7}{2}+2x\right)\cdot\frac{8}{3}=\frac{16}{3}\)
\(\frac{7}{2}+2x=\frac{16}{3}:\frac{8}{3}\)
\(2x=2-\frac{7}{2}\)
\(x=\frac{-3}{2}:2\)
\(x=-3\)
xin lỗi câu b kết quả của mình bị sai
đáp án \(\frac{-3}{4}\)
