Question

Mn ơi giúp mk vs mk cần gấp nka

Tìm x biết .

\(\dfrac{x+5}{2017}+\dfrac{x+4}{2018}+\dfrac{x+3}{2019}=-3\)

Mn ai bt thì giúp nka mk cảm ơn trc

Answer 1

\(\dfrac{x+5}{2017}+\dfrac{x+4}{2018}+\dfrac{x+3}{2019}=-3\\ \dfrac{x+5}{2017}+1+\dfrac{x+4}{2018}+1+\dfrac{x+3}{2019}=-3+3\\ \dfrac{x+5}{2017}+\dfrac{2017}{2017}+\dfrac{x+4}{2018}+\dfrac{2018}{2018}+\dfrac{x+3}{2019}+\dfrac{2019}{2019}=0\\ \dfrac{x+2022}{2017}+\dfrac{x+2022}{2018}+\dfrac{x+2022}{2019}=0\\ x+2022.\left(\dfrac{1}{2017}+\dfrac{1}{2018}+\dfrac{1}{2019}\right)=0\)

⇒x+2022=0 (vì \(\dfrac{1}{2017}+\dfrac{1}{2018}+\dfrac{1}{2019}\)\(\ne0\))

⇒x=0-2022

⇒x=-2022