+) C2H5OH
%C=\(\dfrac{2.C}{C2H5OH}\cdot100\%=\dfrac{2\cdot12}{46}\cdot100\%=52.17\%\)
\(\%H=\dfrac{6H}{C2H5OH}\cdot100\%=\dfrac{6\cdot1}{46}\cdot100\%=13.04\%\)
\(\%O=\dfrac{1.O}{C2H5OH}\cdot100\%=\dfrac{16}{46}100\%=34.78\%\)
+) CH3COOH chứ nhỉ? Bạn làm tương tự như trên thôiiii
* C2H5OH
%C = \(\dfrac{12.2.100}{46}\approx52,2\%\)
\(\%_H=\dfrac{6.100}{46}\approx13\%\)
\(\%_O=\dfrac{16.100}{46}\approx34,8\%\)
* CH3COOH
\(\%_C=\dfrac{12.2.100}{60}=40\%\)
\(\%_H=\dfrac{4.100}{60}\approx6,7\%\)
\(\%_O=\dfrac{16.2.100}{60}\approx53,3\%\)