\(x+\left(x+1\right)+\left(x+2\right)+.....+\left(x+99\right)=5450\)
\(\Leftrightarrow\left(x+x+.....+x\right)+\left(1+2+....+99\right)=5450\)
\(\Leftrightarrow100x+\dfrac{\left(99+1\right).99}{2}=5450\)
\(\Leftrightarrow100x+4950=5450\)
\(\Leftrightarrow x=5\)
Vậy..