$(x+2)(x+3)-(x-2)(x+5)$
$=(x^2+5x+6)-(x^2+3x-10)$
$=2x+16$
\(\left(x+2\right)\left(x+3\right)-\left(x-2\right)\left(x+5\right)\)
\(=x^2+3x+2x+6-\left(x^2+5x-2x-10\right)\)
\(=x^2+3x+2x+6-\left(x^2+3x-10\right)\)
\(=x^2+3x+2x+6-x^2-3x+10\)
\(=2x+16\)
\(\left(x+2\right)\left(x+3\right)-\left(x-2\right)\left(x+5\right)\)
= \(x^2+5x+6-\left(x^2+3x-10\right)\)
= \(x^2+5x+6-x^2-3x+10\)
= 2x + 16
= 2 ( x + 8)