\(x\left(2x-1\right)\left(x+3\right)=0\)
\(\Leftrightarrow x=0;2x-1=0;x+3=0\)
*) \(2x-1=0\)
\(\Leftrightarrow x=\dfrac{1}{2}\)
*) \(x+3=0\)
\(\Leftrightarrow x=-3\)
Vậy \(x=0;x=\dfrac{1}{2};x=-3\)
Ta có: \(x\left(2x-1\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\2x-1=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{2}\\x=-3\end{matrix}\right.\)
Vậy: \(S=\left\{0;\dfrac{1}{2};-3\right\}\)