Bài 4: Phương trình tích
Các câu hỏi tương tự
1. x^4+x^2-2=0; 2. x^3+3x^2+6x+4=0; 3. x^3-6x^2+8x=0; 4. x^4-8x^3-9x^2=0 Giúp với (;~;)
a) ( x+5)(2x-3)=0
b) ( x^2+1)(6x+3)=0
C) 2(x+3)(x-4)=0
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Giải phương trình:
13. 6x5-29x4+27x3+27x2-29x+6=0
14. 125x3-(2x+1)3-(3x-1)3=0
15. (x-3)3+(x+1)3=8(x-1)3
Giải phương trình
a) \(x^3-3x^2+3x-1+x\left(x^2-x\right)=0\)
b) \(x^2+x-12=0\)
c) \(6x^2-11x-10=0\)
a) (2x +1)(3 – x)(4 - 2x) = 0 b)2x(x – 3) + 5(x – 3) = 0
c) (x2 – 4) – (x – 2)(3 – 2x) = 0 d) x2 – 5x + 6 = 0
e) (2x + 5)2 = (x + 2)2 f) 2x3 + 6x2 = x2 + 3x
a) 5x + 6 = 0
b) 9x - 3 = 6x + 21
c) x^3 - 9x = 0
d) 1/x-2 - x^2 -4 /4-x^2= 0
giải pt
1.(x^2-x+1)(X^2-x+2)2
2.X(x+2)(x+3)(x+5)280
3.(x+3)(x+4)(X+5)x
4.dfrac{1}{xleft(x+2right)}+dfrac{1}{left(x+2right)left(x+4right)}+dfrac{1}{left(x+4right)left(x+6right)}dfrac{1}{9} 5. 12/x^2-12/x^2+21 6.(x^2-6x)^2+14(x-...
Đọc tiếp
giải pt
1.(x^2-x+1)(X^2-x+2)=2
2.X(x+2)(x+3)(x+5)=280
3.(x+3)(x+4)(X+5)=x
4.\(\dfrac{1}{x\left(x+2\right)}+\dfrac{1}{\left(x+2\right)\left(x+4\right)}+\dfrac{1}{\left(x+4\right)\left(x+6\right)}=\dfrac{1}{9}\) 5. 12/x^2-12/x^2+2=1 6.(x^2-6x)^2+14(x-3)^2=81 7.(x^2+5x)^2-2(x^2+5x)-24=0
8. x^2+2x+3=(x^2+x+1)(X^4+x^2+4)
a,x^2-9x+20=0
b,x^3-4x^2+5x=0
c,x^2=2x-15=0
d,(x^2-1)^2=4x+1
e,4x^3-9x^2+6x-1=0
f,x^4-4x^3-x^2+16x-12=0
1) x3-x2-2=0
2) 4x2-12x+5=0
3) x4+6x2+8=0
4) x3-x2-21x+45=0