\(\dfrac{x+1}{x-2}-\dfrac{5}{x+2}=\dfrac{12}{x^2-4}+1\)
\(\Leftrightarrow\left(x+1\right)\left(x+2\right)-5\left(x-2\right)=12+\left(x+2\right)\left(x-2\right)\)\(\Leftrightarrow x^2+2x+x+2-5x+10=12+x^2-4\)\(\Leftrightarrow x^2+2x+x-5x-x^2=12-4-2-10\)\(\Leftrightarrow-2x=-4\)
\(\Leftrightarrow x=2\)
Vậy \(S=\left\{2\right\}\)
giải phương trình
a. x-1/x^2 -x +1 - x+1/x^2 +x +1 = 10 / x(x^4 +x^2 +1)
b. x+9/10 + x+10/9 = 9/x+10 + 10/x+9
c. x-5/x-5 + x-6/x-5 + x-7/x-5 +...+1/x-5 =4 (x thuộc N)
d. 1/x^2 +3x+2 + 1/x^2 +5x+6 + 1/x^2 +7x+12 +...+ 1/x^2 +15x+56=1/14
Giải phương trình chứa ẩn ở mẫu:
a. (x+1)/(x-2) - (x-1)(x+2) = 2(x2 + 2)/(x2 - 4)
b. (2x+1)/(x-1) = 5(x-1)/(x+1)
c. (x-1)/(x+2) - (x)/(x-2) = (5x-2)/(4 - x2)
d. (x-2)/(2+x)-(3)/(x-2)= 2(x-11)/(x2 - 2)
e. (x-1)/(x+1)-(x2 + x - 2)/(x+1)= (x+1)/(x-1) - x - 2
f. (x+1)/(x-1)-(x-1)/(x+1)=(4)/(x2 - 1)
g. (3)/4(x-5) + (15)/(50-2x2)= - (7)/6(x+5)
h. (12)/(8+x3)= 1 + (1)/(x+2)
k. (x+25)/(2x2 - 50)-(x+5)(x2 - 5x)= (5-x)(2x2 + 10x)
a.\(\frac{x+1}{x-1}-\frac{x-1}{x+1}=\frac{16}{x^2-1}\)
b.\(\frac{12}{x^2-4}-\frac{x+1}{x-2}+\frac{x+7}{x+2}=0\)
c.\(\frac{12}{8-x^3}=1+\frac{1}{x+2}\)
d.\(\frac{x+25}{2x^2-50}-\frac{x+5}{x^2-5x}=\frac{5-x}{2x^2+10x}\)
e.\(\frac{4}{x^2+2x-3}=\frac{2x-5}{x+3}-\frac{2x}{x-1}\)
\(a,\dfrac{1}{x^2+3x+2}-\dfrac{3}{x^2-x-2}=\dfrac{-1}{x^2-4}\)
\(b,\dfrac{2x-1}{x^2+4x-5}+\dfrac{x-2}{x^2-10x+9}=\dfrac{3x-12}{x^2-4x-45}\)
5.c) \(\dfrac{x+1}{x^2+x+1}-\dfrac{x-1}{x^2-x-1}=\dfrac{3}{x\left(x^4+x^2+1\right)}\)
6.b) \(\dfrac{4}{2x^3+3x^2-8x-12}-\dfrac{1}{x^2-4}-\dfrac{4}{2x^2+7x+6}+\dfrac{1}{2x+3}=0\)
\(a.\dfrac{y-1}{y-2}-\dfrac{5}{y+2}=\dfrac{12}{y^2-4}+1\)
\(b.\dfrac{1}{x-1}-\dfrac{3x^2}{x^3-1}=\dfrac{2x}{x^2+x+1}\)
a)\(\dfrac{12}{x^2-4}-\dfrac{x+1}{x-2}+\dfrac{x+7}{x+2}=0\)
b)\(\dfrac{12}{8+x^3}=1+\dfrac{1}{x+2}\)
c)\(\dfrac{x+25}{2x^2-50}-\dfrac{x+5}{x^2-5x}=\dfrac{5-x}{2x^2+10x}\)
Giúp nha mn
Bài 2:giải các pt chứa ẩn ở mẫu sau:
a)\(\dfrac{x+1}{x-1}-\dfrac{x-1}{x+1}=\dfrac{16}{x^2-1}\)
b)\(\dfrac{12}{x^2-4}-\dfrac{x+1}{x-2}+\dfrac{x+7}{x+2}=0\)
c)\(\dfrac{12}{8+x^3}=1+\dfrac{1}{x+2}\)
d)\(\dfrac{x+25}{2x^2-50}-\dfrac{x+5}{x^2-5x}=\dfrac{5-x}{2x^2+10x}\)
Giúp mk nha
Giải các phương trình
1/ \(\dfrac{1}{x^2+3x+2}+\dfrac{1}{x^2+5x+6}+\dfrac{1}{x^2+7x+12}=\dfrac{1}{6}\)
2/ \(\dfrac{1}{x^2-6x+8}+\dfrac{1}{x^2-10x+24}+\dfrac{1}{x^2-14x+48}=\dfrac{1}{9}\)
3/ \(\dfrac{1}{x^2-3x+3}+\dfrac{2}{x^2-3x+4}=\dfrac{6}{x^2-3x+5}\)
4/ \(\dfrac{6}{\left(x+1\right)\left(x+2\right)}+\dfrac{8}{\left(x-1\right)\left(x+4\right)}=1\)
5/ \(4\left(x^3+\dfrac{1}{x^3}\right)=13\left(x+\dfrac{1}{x}\right)\)
6/ \(\dfrac{4x}{4x^2-8x+7}+\dfrac{3x}{4x^2-10x+7}=1\)
7/ \(\dfrac{x^2-3x+5}{x^2-4x+5}-\dfrac{x^2-5x+5}{x^2-6x+5}=-\dfrac{1}{4}\)
8/ \(x.\dfrac{8-x}{x-1}\left(x-\dfrac{8-x}{x-1}\right)=15\)
