Bài 5: Phương trình chứa ẩn ở mẫu
Các câu hỏi tương tự
Giải phương trình : \(\dfrac{\left(2007-x\right)^2+\left(2007-x\right)\left(x-2008\right)+\left(x-2008\right)^2}{\left(2007-x\right)^2-\left(2007-x\right)\left(2008-x\right)+\left(x-2008\right)^2}\)=\(\dfrac{19}{49}\)
a) 5-4x=3x-9
b) (x-4)(3x+9)=0
c) (x/(x+4))+(12/(x-4))=(4x+48)/(x*x-16)
d) 4-2x=7-x
e) (x+4)(8-4x)=0
f) (x/(x+5))+(11/(x-5))=(x+55)/(x*x-25)
g) ((3x+2)/2) - ((3x+1)/6)= (5/3) +2x
h) 2x-(3-5x)=4(x+3)
i) 3x -6+x=9-x
k) 2t-3+5t= 4t+12
m.n giúp mik ạ ...
a. \(\dfrac{x+3}{x-3}-\dfrac{x-3}{x+3}=\dfrac{9}{x^2-9}\)
b. \(\dfrac{x+2}{4}-x+3=\dfrac{1-x}{8}\)
c. / 2x + 3 / = x + 2
d. \(\dfrac{2x-1}{3}-x-1=\dfrac{x+2}{4}\)
e.\(\dfrac{x-4}{x-1}+\dfrac{x+4}{x+1}=2\)
f. \(\dfrac{3x}{x-2}+\dfrac{3x}{\left(x-2\right)\left(x-5\right)}=\dfrac{x}{x-5}\)
ai giúp mik với mik nhiều bt lắm
a, 1/x-1 - 7/x+2 = 3/x2+x-2
b,x+3/x-4 + x-1/x-2 = 2/6x-8-x2
c,1/x+1 + 2/x3-x2x+1 = 3/1-x2
d, 3x-1/x-1 - 2x+5/x+3 = 1 - 4/x2+2x-3
e, x2+2x+1/x2+2x+2 + x2+2x+2/x2+2x+3 = 7/6
f, 1/4x2-12x+9 - 3/9-4x2=4/4x2+12x+9
1) dfrac{4x+7}{x-1} dfrac{12x+5}{3x+4}2) dfrac{x}{x-1} - dfrac{2x}{x^{2^{ }}-1} 03) dfrac{1}{3-x} - dfrac{14}{x^2-9} 14) dfrac{x+1}{x-1} - dfrac{x-1}{x+1} dfrac{4}{x^2-1}5) x + dfrac{1}{x} x2 + dfrac{1}{x^2}6) dfrac{x-1}{x^2+4} dfrac{x-1}{x+1}
Đọc tiếp
1) \(\dfrac{4x+7}{x-1}\) = \(\dfrac{12x+5}{3x+4}\)
2) \(\dfrac{x}{x-1}\) - \(\dfrac{2x}{x^{2^{ }}-1}\) = 0
3) \(\dfrac{1}{3-x}\) - \(\dfrac{14}{x^2-9}\) = 1
4) \(\dfrac{x+1}{x-1}\) - \(\dfrac{x-1}{x+1}\) = \(\dfrac{4}{x^2-1}\)
5) x + \(\dfrac{1}{x}\) = x2 + \(\dfrac{1}{x^2}\)
6) \(\dfrac{x-1}{x^2+4}\) = \(\dfrac{x-1}{x+1}\)
giải phương trình sau:
a) \(\dfrac{8}{x-8}+\dfrac{11}{x-11}=\dfrac{9}{x-9}+\dfrac{10}{x-10}\)
b) \(\dfrac{x}{x-3}-\dfrac{x}{x-5}=\dfrac{x}{x-4}-\dfrac{x}{x-6}\)
c) \(\dfrac{4}{x^2-3x+2}-\dfrac{3}{2x^2-6x+1}+1=0\)
d) \(\dfrac{1}{x-1}+\dfrac{2}{x-2}+\dfrac{3}{x-3}=\dfrac{6}{x-6}\)
Giải pt:
a) \(\dfrac{x+1}{x^2+2x+4}-\dfrac{x-2}{x^2-2x+4}=\dfrac{6}{x(x^4+4x^2+16)}\)
b) \(\dfrac{4x^{2} + 10}{x^{2} + 5} - \dfrac{9}{x^{2} + 4} = \dfrac{8}{x^{2} + 3} + \dfrac{6}{x^{2} + 1}\)
giải phương trình
a. x-1/x^2 -x +1 - x+1/x^2 +x +1 = 10 / x(x^4 +x^2 +1)
b. x+9/10 + x+10/9 = 9/x+10 + 10/x+9
c. x-5/x-5 + x-6/x-5 + x-7/x-5 +...+1/x-5 =4 (x thuộc N)
d. 1/x^2 +3x+2 + 1/x^2 +5x+6 + 1/x^2 +7x+12 +...+ 1/x^2 +15x+56=1/14
1. a. 4x-20=0
b. 2x+x+12=0
c. x-5=3-x
d. 7-3x=9-x
2.
a. 7+2x=22-3x
b. 8x-3=5x+12
c. x-12+4x=25+2x-1
d. x+2x+3x-19=3x+5
e. 7-(2x+4)=-(x+4)
f. (x-1)-(2x-1)=9-x