Question

x+ \(\dfrac{1}{3}\)<3x - \(\dfrac{5}{3}\)

Answer 1

Ta có:x+\(\dfrac13\)<3x-\(\dfrac53\)<=>x+2<3x<=>2x>2

<=>x>1

Vậy S={x/x>1}

Answer 2

\(x+\dfrac{1}{3}< 3x-\dfrac{5}{3}\)

\(\Leftrightarrow x-3x< \dfrac{-5}{3}-\dfrac{1}{3}\)

\(\Leftrightarrow\) \(-2x< -2\)

\(\Leftrightarrow x>1\)

Vậy nghiệm của pt là \(x>1\)