Câu hỏi của Le Na Tran

Question

$\dfrac{2x-\dfrac{4-3x}{5}}{2}=\dfrac{7x-\dfrac{x-3}{2}}{5}-x+1$

giải phương trình sau

Nhã Doanh · Accepted Answer

$\dfrac{2x-\dfrac{4-3x}{5}}{2}=\dfrac{7x-\dfrac{x-3}{2}}{5}-x+1$

$\Leftrightarrow\dfrac{\dfrac{10x-4+3x}{5}}{2}=\dfrac{\dfrac{14x-x+3}{2}}{5}-x+1$

$\Leftrightarrow\dfrac{\dfrac{13x-4}{5}}{2}=\dfrac{\dfrac{13x+3}{2}}{5}-x+1$

$\Leftrightarrow\dfrac{13x-4}{10}=\dfrac{13x+3}{10}-\dfrac{10x}{10}+\dfrac{10}{10}$

$\Leftrightarrow13x-4-13x-3+10x-10=0$

$\Leftrightarrow10x-17=0$

$\Leftrightarrow x=\dfrac{17}{10}$Câu trả lời: $\dfrac{2x-\dfrac{4-3x}{5}}{2}=\dfrac{7x-\dfrac{x-3}{2}}{5}-x+1$

$\Leftrightarrow\dfrac{\dfrac{10x-4+3x}{5}}{2}=\dfrac{\dfrac{14x-x+3}{2}}{5}-x+1$

$\Leftrightarrow\dfrac{\dfrac{13x-4}{5}}{2}=\dfrac{\dfrac{13x+3}{2}}{5}-x+1$

$\Leftrightarrow\dfrac{13x-4}{10}=\dfrac{13x+3}{10}-\dfrac{10x}{10}+\dfrac{10}{10}$

$\Leftrightarrow13x-4-13x-3+10x-10=0$

$\Leftrightarrow10x-17=0$

$\Leftrightarrow x=\dfrac{17}{10}$

Bài 2: Phương trình bậc nhất một ẩn và cách giải