\(\dfrac{x-6}{x-4}=\dfrac{x}{x-2}\)
\(ĐK:x\ne4;2\)
\(\Leftrightarrow\dfrac{x-6}{x-4}-\dfrac{x}{x-2}=0\)
\(\Leftrightarrow\dfrac{\left(x-6\right)\left(x-2\right)-x\left(x-4\right)}{\left(x-4\right)\left(x-2\right)}=0\)
\(\Leftrightarrow\left(x-6\right)\left(x-2\right)-x\left(x-4\right)=0\)
\(\Leftrightarrow x^2-2x-6x+12-x^2+4x=0\)
\(\Leftrightarrow-4x=-12\)
\(\Leftrightarrow x=3\left(tm\right)\)
đk : x khác 2 ; 4
\(\Rightarrow x^2-8x+12=x^2-4\Leftrightarrow8x=16\Leftrightarrow x=2\left(ktm\right)\)
-> vậy pt vô nghiệm