\(\left(x-3\right)\left(x+2\right)-x\left(x-5\right)=x^2+2x-3x-6-x^2+5x=4x-6=2\left(2x-3\right)\)
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cháu/em/mình cảm ơn nhiều!
Giải phương trình:
a,(x+3).(x-2)-2(x+1)^2=(x-3)^2-2x^2+4x
b,(x-2)^3+(x-5)(x+5)=x(x^2-5x)-7x-3
c,(x+2)^2-(x+3)(x-4)=5-x(x-3)
d,(x+7)(x-7)-(x+2)^2=5(x+2)+x-7
a, (x-3)^2-4(x-5)=(4-x)^2
b, 3(x-2)(x+2)=(2x-1)^2-(x-3)^2
c, (x+4)^2-(x-5)^2=5(x-4)
d, x(3+x)^2-1=(x+2)^3
Mong mọi người giúp đỡ!
10x+3/12=1+6:8x/9
2x+7x5 5x+1=0
2x(x-5)-x+5=0
(x+3)^2-(5-x)(x+3)=0
(x+2)(3-4x)=x^2+4x+4
giải pt
1.(x^2-x+1)(X^2-x+2)=2
2.X(x+2)(x+3)(x+5)=280
3.(x+3)(x+4)(X+5)=x
4.\(\dfrac{1}{x\left(x+2\right)}+\dfrac{1}{\left(x+2\right)\left(x+4\right)}+\dfrac{1}{\left(x+4\right)\left(x+6\right)}=\dfrac{1}{9}\) 5. 12/x^2-12/x^2+2=1 6.(x^2-6x)^2+14(x-3)^2=81 7.(x^2+5x)^2-2(x^2+5x)-24=0
8. x^2+2x+3=(x^2+x+1)(X^4+x^2+4)
1,Giải PT sau
a, (5x+3)(x2+4)(x-4)=0
b, (4x-1)(x-3)-(x-2)(5x+2)=0
c, (x+3)(x-5)+(x+3)(3x-4)=0
d, (x+6)(3x-1)+x2-36=0
e, 0,75x(x+5)=(x+5)(3-1,25x)
Giải các phương trình sau:
a) (x-1)(3x-7)=(x-1)(x+3)
b) (3x+1)(x-2)=(x-2)(x+1)
c) (x-3)^2 +2x-6=0
d)(2x-1)^2=9
e) x(x-1)=3(x-1)
f)x^2(x-3)=4(x-3)
g) x(x-5)=2(x-5)
Giải phương trình:
a) \(\dfrac{x^2-x-6}{x-3}=0\)
b) \(\dfrac{x+5}{3x-6}-\dfrac{1}{2}=\dfrac{2x-3}{2x-4}\)
c) \(\dfrac{12}{1-9x^2}=\dfrac{1-3x}{1+3x}-\dfrac{1+3x}{1-3x}\)
d) \(\dfrac{x+5}{x-1}=\dfrac{x+1}{x-3}-\dfrac{8}{x^2-4x+3}\)
e) \(\dfrac{x+1}{x-2}-\dfrac{5}{x+2}=\dfrac{12}{x^2-4}+1\)Thể loại truyện
Giải phương trình sau:
(x+5)(x−1)=2x(x−1)
5(x+3)(x−2)−3(x+5)(x+2)=0
\(2x^3+5x^2-3x=0\)
\(\left(x-1\right)^2+2\left(x-1\right)\left(x+2\right)+\left(x+2\right)^2=0\)
1/(2x-1)(3x+2)(5-x)=0
2/(2x+5)(x-4)=(x-5)(4-x)
3/16x^2-8x+1=4(x+3)(4x-1)
4/27x^2(x+3)-12(×^2+3x)=0
5/2(9x^2+6x+1)=(3x+1)(x-2)
6/(2x-1)^2=49
Bài 1 : Giải các phương trình sau:1) 5-(x-6)=4(3-2x) 2) (x-3)(x+4)-2(3x-2)=(x-4)2 3)3-x(1-3x)=5(1-2x) 4)9x-1=(3x+1)(4x+1) 5)2x(x-1)=x2-1 6)x2-5x2+6x=0 7)x2+4x-5=0 8)x3+9x2-4x-36=0
