\( x - 3 + \dfrac{{2\left( {x - 3} \right) - 1}}{3} = \dfrac{{3 - x}}{4}\\ \Leftrightarrow x - 3 + \dfrac{{2x - 7}}{3} = \dfrac{{3 - x}}{4}\\ \Leftrightarrow 12x - 36 + 4\left( {2x - 7} \right) = 3\left( {3 - x} \right)\\ \Leftrightarrow 12x - 36 + 8x - 28 = 9 - 3x\\ \Leftrightarrow 20x - 64 = 9 - 3x\\ \Leftrightarrow 23x = 73\\ \Leftrightarrow x = \dfrac{{73}}{{23}} \)
@Vũ Minh Tuấn sai rồi em nhé!
\(x-3+\frac{2.\left(x-3\right)-1}{3}=\frac{3-x}{4}\)
\(\Leftrightarrow\frac{x-3}{1}+\frac{2.\left(x-3\right)-1}{3}=\frac{3-x}{4}\)
\(\Leftrightarrow\frac{12.\left(x-3\right)}{12}+\frac{4.2.\left(x-3\right)-1}{3.4}=\frac{\left(3-x\right).3}{4.3}\)
\(\Leftrightarrow\frac{12.\left(x-3\right)}{12}+\frac{8.\left(x-3\right)-1}{12}=\frac{\left(3-x\right).3}{12}\)
\(\Rightarrow12.\left(x-3\right)+8.\left(x-3\right)-1=\left(3-x\right).3\)
\(\Leftrightarrow12x-36+8x-24-1=9-3x\)
\(\Leftrightarrow20x-61=9-3x\)
\(\Leftrightarrow20x+3x=9+61\)
\(\Leftrightarrow23x=70\)
\(\Leftrightarrow x=70:23\)
\(\Leftrightarrow x=\frac{70}{23}.\)
Vậy phương trình có tập hợp nghiệm là: \(S=\left\{\frac{70}{23}\right\}.\)
Chúc bạn học tốt!
