(x + 2)(x2 - x + 2)=0
Th1:
x + 2 = 0
x = - 2
Th2:
x2 - x + 2 = 0
x2 - 2 . x . 1/2 + 1/4 + 7/4 = 0
(x - 1/2)2 + 7/4 = 0
(x - 1/2)2 lớn hơn hoặc bằng 0
(x - 1/2)2 + 7/4 lớn hơn hoặc bằng 7/4 > 0
=> loại
Vậy x = - 2
Ta có :
\(\left(x+2\right)\left(x^2-x+2\right)=0\)
\(\left(x+2\right).\left[\left(x^2-2.\frac{1}{2}x+\frac{1}{4}\right)+\frac{7}{4}\right]=0\)
\(\left(x+2\right)\left[\left(x-\frac{1}{2}\right)^2+\frac{7}{4}\right]=0\)
Mà :\(\left(x-\frac{1}{2}\right)^2\ge0\)
\(\Rightarrow\left(x-\frac{1}{2}\right)^2+\frac{7}{4}\ge\frac{7}{4}\)
\(\Rightarrow\left(x-\frac{1}{2}\right)^2+\frac{7}{4}>0\)
\(\Rightarrow x+2=0\)
\(\Rightarrow x=-2\)