Question

(x-2)(2x-3) =(4-2x)(x-2)

Giúp

Answer 1

PT <=> (x-2)(2x-3) - (4 - 2x)(x-2) = 0

<=> (x - 2)(2x - 3 - 4 +2x) = 0

<=> (x - 2)(4x - 7) = 0

<=> \(\left[{}\begin{matrix}x-2=0\\4x-7=0\end{matrix}\right.=>\left[{}\begin{matrix}x=2\\x=\frac{7}{4}\end{matrix}\right.\)

Answer 2

giải phương trình:

(x-2)(2x-3) =(4-2x)(x-2)

<=> (x-2)(2x-3) - (4 - 2x)(x-2) = 0

<=> (x - 2)(2x - 3 - 4 +2x) = 0

<=> (x - 2)(4x - 7) = 0

<=> (x-2)=0=>x=2

<=> 4x-7=0=>x=\(\frac{7}{4}\)

Vậy S=\(\left\{2;\frac{7}{4}\right\}\)