Ta có: \(\left|x-2\right|=0\)
\(\Rightarrow x-2=0\)
\(\Rightarrow x=0+2\)
\(\Rightarrow x=2\)
Vậy \(x=2.\)
|x - 2| = 0
TH 1:
x - 2 = 0
x = 0 + 2
x = 0
TH 2 :
x- 2 = - 0
( giống TH 1)
TH : Trường hợp
| x - 2| = 0
\(\Rightarrow x-2=0\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
|x-2|=0
\(\Rightarrow\)x-2\(\in\)\(\left\{-2,+2\right\}\)
\(\Rightarrow\)x-2=2\(\Rightarrow\)x=4
\(\Rightarrow\)x-2=-2\(\Rightarrow\)x=0
\(\Rightarrow\)x\(\in\)\(\left\{4,0\right\}\)
