Question

/x - 2 /+ 1 = 5

trả lời nhanh giùm mình ai nhanh nhất mình sẽ like

Answer 1

\(\left|x-2\right|+1=5\Leftrightarrow\left|x-2\right|=4\Leftrightarrow\left[{}\begin{matrix}x-2=4\\x-2=-4\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-2\end{matrix}\right.\)

Vậy \(\left[{}\begin{matrix}x=6\\x=-2\end{matrix}\right.\)

Answer 2

|x-2|+1=5

⇒|x-2|=4

⇒\(\left[{}\begin{matrix}x-2=4\\x-2=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=6\\x=-2\end{matrix}\right.\)

Vậy x∈\(\left\{-2,6\right\}\)

Answer 3

\(\left|x-2\right|\) + 1 = 5

\(\left|x-2\right|\) = 5 - 1

\(\left|x-2\right|\) = 4

=> x - 2 ∈ { -4 ; 4 }

=> x ∈ { -2 ; 6 }

Answer 4

|x-2|+1=5

\(\Leftrightarrow\) |x-2|= 5-1

\(\Leftrightarrow\) |x-2|=4

\(\Rightarrow\) x-2=4 hoặc x-2=-4

\(\Leftrightarrow\) x-2=4 \(\Leftrightarrow\) x-2=-4

\(\Leftrightarrow\) x = 4+2 \(\Leftrightarrow\) x =-4+2

\(\Leftrightarrow\) x = 6. \(\Leftrightarrow\) x = -2.

Vậy x \(\in\) \(\left\{6;-2\right\}\)